The best answer I could find was when you Google it, that the fuse is of poor quality. I cannot leave you a link, but you can find it for yourself. Put in poor quality fireworks and all sorts of things will pop up. No pun intended.
Answer:
Option C. Energy Profile D
Explanation:
Data obtained from the question include:
Enthalpy change ΔH = 89.4 KJ/mol.
Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)
ΔH = Hp – Hr
Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.
If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.
Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.
Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.
<span> aluminum is an element. All elements are pure substances, so that means they are homogenous.
please mark as brainliest
</span>
Answer:
Approximately
.
Explanation:
Balanced equation for this reaction:
.
Look up the relative atomic mass of elements in the limiting reactant,
, as well as those in the product of interest,
:
Calculate the formula mass for both the limiting reactant and the product of interest:
.
.
Calculate the quantity of the limiting reactant (
) available to this reaction:
.
Refer to the balanced equation for this reaction. The coefficients of the limiting reactant (
) and the product (
) are both
. Thus:
.
In other words, for every
of
formula units that are consumed,
of
formula units would (in theory) be produced. Thus, calculate the theoretical yield of
in this experiment:
.
Calculate the theoretical yield of this experiment in terms of the mass of
expected to be produced:
.
Given that the actual yield in this question (in terms of the mass of
) is
, calculate the percentage yield of this experiment:
.
Carbon is an atom so electrons=protons
<span>First shell has 2 electrons and the next 8 so with 6 electrons the first shell fills and 4 are left to go into the 2th shell.</span>