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m_a_m_a [10]
3 years ago
6

An electromagnetic wave that has a higher frequency than ultraviolet light will have ____ than the ultraviolet light.

Chemistry
1 answer:
8_murik_8 [283]3 years ago
5 0
C)shorter wavelength and higher energy
frequency is inversely proportional to wavelength
frequency is directly proportional to Energy
You might be interested in
Given following electron configurations, 1s22s22p63s23p64s23d104p65s24d9 and 1s22s22p63s23p64s23d104p65s14d10.
marusya05 [52]

Explanations:- Part 1: We could count the total number of electrons by looking at the electron configurations. Both of these electrons configurations have 47 electrons. If we look at the periodic table then 47 is the atomic number of silver. So, the name of the element is silver and its represented as Ag.

Part 2: As per the rule, Completely filled and half filled orbitals are more stable. First electron configuration has 9 electrons in 4d and we know that d is more stable if it has 5 electrons(half filled) or it has 10 electrons(full filled).

For stability reasons, one of the electron from 5s goes to 4d and for this reason the second electron configuration is found most often in nature for silver.

Few other examples are Cr and Cu.

8 0
3 years ago
Covalent bonds take place between..
umka2103 [35]

Answer:

Covalent Bonds are formed when two non-metals share electrons

Hope this helps

7 0
3 years ago
The length of a covalent bond depends upon the size of the atoms and the bond order.
lukranit [14]

Answer:

True

Explanation:

The length of covalent bond depends upon the size of atoms and the bond order.

6 0
3 years ago
Earth has approximately 600,000,000 meters of coastline. If we assume this entire length of coastline has sandy beaches 60 meter
VashaNatasha [74]

Answer:

7 and 11

Explanation:

The amount of sand on the beaches can be found using this formula:

volume (m3) = length (m) × width (m) × depth (m)

(6 × 108 m) × 60 m × 20 m = 7 × 1011 m3

Therefore, there would be a total of 7 × 1011 cubic meters of sand on the beaches.

4 0
3 years ago
Using the standard enthalpies of formation found in the textbook, determine the enthalpy change for the combustion of ethanol c2
ArbitrLikvidat [17]
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)

Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol

Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol

<em>Answer: -1367.5 kJ/mol</em>
6 0
3 years ago
Read 2 more answers
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