Answer : The molecular formula of the compound will be, 
Explanation :
Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.
Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.
For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.
The equation used to calculate the valency is :
As we are given that the empirical formula of a compound is 
and the molar mass of compound is, 90.09 gram/mol.
The empirical mass of = 1(12) + 2(1) + 1(16) = 30 g/eq
Molecular formula = 
Thus, the molecular formula of the compound will be,
Answer: When the reaction reaches equilibrium, the cell potential will be 0.00 V
Explanation:
Equilibrium state is the state when reactants and products are present but the concentrations does not change with time.
The equilibrium is dynamic in nature and the reactions are continuous in nature. Rate of forward reaction is equal to the rate of backward reaction.
The standard emf of a cell is related to Gibbs free energy by following relation:
The Gibbs free energy is related to equilibrium constant by following relation:
For equilibrium 
Thus 
Thus When the reaction reaches equilibrium, the cell potential will be 0.00 V
The ionization energy for a hydrogen atom in the n = 2 state is 328 kJ·mol⁻¹.
The <em>first ionization energy</em> of hydrogen is 1312.0 kJ·mol⁻¹.
Thus, H atoms in the <em>n</em> = 1 state have an energy of -1312.0 kJ·mol⁻¹ and an energy of 0 when <em>n</em> = ∞.
According to Bohr, Eₙ = k/<em>n</em>².
If <em>n</em> = 1, E₁= k/1² = k = -1312.0 kJ·mol⁻¹.
If <em>n</em> = 2, E₂ = k/2² = k/4 = (-1312.0 kJ·mol⁻¹)/4 = -328 kJ·mol⁻¹
∴ The ionization energy from <em>n</em> = 2 is 328 kJ·mol⁻¹
.
Answer:
4
Explanation:
in order for the bobber to float,it must be less dense, and for the line to sink, it must be more dense.
Answer:
Na^+
Explanation:
The symbol for sodium is Na. The term "sodium ion" assumes that the reader knows that sodium's single 3s electron is susceptible to theft by any nearby element that has a high electron affinity. Sodium's ionization energy is low, allowing the 3s electron to move elsewhere and leave behinf a positively charged Na^+ atom.
