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3 years ago

Which is the electron configuration for lithium? 1s2 2s3

Chemistry

2 answers:

guajiro [1.7K]3 years ago

8 0

The answer is this question is the first one put it's put like this 2s1

Lunna [17]3 years ago

3 0

Answer:

It is 1s^2 2s^1 don't listen to other guy i took edgenuity test

Explanation:

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Which of the following elements would require the most energy to

umka2103 [35]

Option D: Chromium would require the most energy to convert one mole of gaseous atoms into gaseous ions each carrying two positive charges.

<h3>What does the term “ionization energy” mean? </h3>

The ionization energy measures an element’s ability for participating in any chemical processes that calls up for the creation of ions or the donation of other electrons.

It is defined as the energy that any electron present in a gaseous atom or ion has in order to absorb so that it comes out of the influence of the nucleus and hence freely move

Ionization energy is also said as the minimum energy required to remove the most loosely bound electron that is present in an isolated gaseous atom or a positive ion or a molecule.

It can be easily connected to the type of chemical bonds that exist between the components in the compounds that they form.

<h3>Which element ionizes most energetically?</h3>

Helium, because it has the highest first ionization energy, whereas francium has one of the lowest.

To know more about Ionization energy visit:

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8 0

1 year ago

If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe

pishuonlain [190]

Answer:

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.

Mᵣ: 30.01 32.00 46.01

2NO + O₂ ⟶ 2NO₂

Mass/g: 80.00 16.00

2. Calculate the moles of each reactant

$\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}$

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

$\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}$

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

$\text{Moles of NO}_{2} = \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}$

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

$\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}$

(b) Mass of NO reacted

$\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}$

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0

3 years ago

How many atoms of hydrogen are there in 18g of water ?

Bingel [31]

Answer:

They are 1.204×10^24 atoms of hydrogen present in 18 grams of water. In order to calculate this,it is necessary to compute the number of hydrogen moles present in the sample.

6 0

3 years ago

Suppose you have a sample of table salt (NaCl) that has a mass of 100.0 grams. If

IgorC [24]

Taking into account the definition of molarity, the concentration of the solution is 0.855 $\frac{moles}{liter}$ .

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

$Molarity=\frac{number of moles}{volume}$