A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m

Question

3 years ago

11

A speedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. It began the trip at a speed of 0 m

/s. By the time it reached the buoy, it was going 10 m/s. What was the average velocity of the boat? -3.33 m/s2 -1.11 m/s +1.11 m/s +3.33 m/s

Physics

2 answers:

LenaWriter [7] · Answer 1 · 2022-07-22T06:31:37+03:00

LenaWriter [7]3 years ago

5 0

So as a fact we do not know if the boat "burned tires" to reach the buoy :) the average velocity is +1,11 m/s. 20m divided by 18 seconds is +1.11 m/s

MaRussiya [10] · Answer 2 · 2022-07-22T08:19:52+03:00

Answer:

<h2>The average velocity is +1.11 m/s.</h2>

Explanation:

The average speed is define as the total distance traveled divided by the total time spends, from the problem we know that the total distance is 20 meters, and the total time is 18 seconds, we just have to find the quotient between and them:

$v=\frac{total \ distance}{total \ time}\\v=\frac{20m}{18sec}=1.11\frac{m}{s}$

Therefore the average velocity is +1.11 m/s.