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Alex787 [66]
3 years ago
12

Which best describes how geothermal energy is used to make electricity?. . A.. Rocks are split to release energy that drives a s

team turbine attached to an electrical generator.. . B.. Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator.. . C.. Heat energy from below the ground drives liquid water though a turbine attached to an electrical generator.. . D.. Heat energy from below ground heats and presuurizes air that drives a turbine attached to an electrical generator..
Physics
1 answer:
In-s [12.5K]3 years ago
6 0
Answer is b that is  Heat energy from below the ground converts water to steam to drive a steam turbine attached to an electrical generator.. . 
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A spacecraft travels at 1.5 X 108 m/s relative to Earth. A process onboard the
kvasek [131]

Answer:

73.6 minutes

Explanation:

relative time = time interval / √(1 - observer velocity² / speed of light²)

we have relative time. we want time interval.

rearrange

time interval = relative time x √(1 - observer velocity² / speed of light²)

convert 85 mins into seconds

85 x 60 = 5100

1.5 x 10⁸ as a number is 150000000

for c = 299 792 458

time interval = 5100 x √(1 - 150 000 000² / 299 792 458²)

for c = 3 x 10⁸

time interval = 5100 x √(1 - 150 000 000² / 300 000 000²)

time interval = 5100 x 0.866

time interval = 4415.71

divide by 60 for back into minutes

time = 73.6 minutes

4 0
2 years ago
Transforma la siguiente unidad al sistema internacional:<br> 37 ft3
tigry1 [53]
F up HC Chi UC Chi UC CI UC CJ
3 0
3 years ago
A dragster runs the quarter mile in 8.96 s. What is the car's velocity (in ft/s) at the finish line?
lara [203]
The first thing you should know to answer this question is the following conversion:
 1mi = 5280feet
 We have then that the speed is:
 v = ((1/4) * (5280)) / (8.96)
 v = 147.32 feet / s
 Answer:
 the car's velocity (in ft / s) at the finish line is 147.32 feet / s
7 0
3 years ago
A circular loop of wire with a radius of 15.0 cm and oriented in the horizontal xy-plane is located in a region of uniform magne
bekas [8.4K]

Answer:

Explanation:

Given that,

Radius r = 15cm = 0.15m

Area of the circular loop can be determined using the formula for area of a circle

A = π r²

A = π × 0.15²

A = 0.0708 m²

Magnetic field B = 1.2T in positive z direction

B = 1.2 •k T.

If loop is remove from the field in the time interval

∆t = 2.3ms = 2.3×10^-3s

We want to find the average EMF and it is given as

ε = —∆Φ/∆t

The final flux is zero

Φf = 0

Where magnetic flux is given as

Φi = BA Cosθ

Where θ=0 since the area and the magnetic field point in the same direction.

Φi = BA Cos0

Φi = BA

Φi = 1.2 × 0.0708

Φi = 0.0848 Vs

Then, ε = —∆Φ/∆t

ε = —(Φf — Φi) / ∆t

ε = —(0-0.0848) / (2.3×10^-3)

ε = 0.0848 / (2.3×10^-3)

ε = 36.88 V

The EMF is 36.88 Volts

6 0
3 years ago
Which qualifications are typical for a Manufacturing career? Check all that apply.
kicyunya [14]
D should be the answer
8 0
3 years ago
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