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4 years ago

During the formation of a tornado,

Chemistry

2 answers:

mihalych1998 [28]4 years ago

8 0

Answer: Option (4)

Explanation: For the formation of a tornado, warm air must meet the cold air.

Initially, the warm air present in the lower atmosphere, gets heated up, being less dense, rises up and mixes up with the cold and denser air mass present in the upper atmosphere. Due to this collision of both the air masses, and the presence of water vapor, it gets converted into water droplets and formation of clouds. With time a more intense funnel forms due to the wind from all direction and forms a tornado.

Thus, the correct answer is option (4).

o-na [289]4 years ago

7 0

The very last option is the correct answer.

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<h3><u>Unders</u><u>tanding</u><u> </u><u>the</u><u> </u><u>conc</u><u>ept</u><u>:</u><u>-</u></h3>

Here the concept of Molarity used .We will put the formula of Molarity then we find moles of copper sulphate .Then we can find the.Given weight of Copper sulphate.So let's do

<h3>Solution:-</h3>

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We know

$\boxed{\sf Molarity=\dfrac{Moles\:of\: solute}{Volume\:of\: Solvent \:in\;L}}$

$\\ \rm\longmapsto Moles\:of\: solute=Molarity\times Volume\:of\: Solvent\:in\:L$

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$\\ \rm\longmapsto Moles\:of\: Solute=0.48mol$

Now

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$\\ \rm\longmapsto 65u+32u+4(16u)+5(2\times 1u+16u)$

$\\ \rm\longmapsto 96u+64u+5(2+16)$

$\\ \rm\longmapsto 160u+90u$

$\\ \rm\longmapsto 250u$

$\\ \rm\longmapsto 250g/mol$

Now

$\boxed{\sf No\:of\:moles=\dfrac{Given\:Mass}{Molar\:Mass}}$

$\\ \rm\longmapsto Given\:Mass=No\:of\:Moles\times Molar\:Mass$

$\\ \rm\longmapsto Given\:Mass=250(0.48)$

$\\ \rm\longmapsto Given\:Mass=120g$

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