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Ray Of Light [21]
3 years ago
15

Chemistry!! Help please!!

Chemistry
1 answer:
Flura [38]3 years ago
4 0
1. The conjugate acid-base pairs are HCl/Cl- and NH3/NH4+. They can be changed into one another by proton transfer.

2. The acid in the reaction is the molecule that has the lowest pKa value or (simply) gives their proton away the easiest. The pKa of HCl is around 3 I think while ammonia’s is around 35. This means HCl is the acid here. In the other reaction (backwards) you can see that NH4+ gives a proton to the chloride ion. To give a proton = acid. So the acids are HCl and NH4+ and the bases are NH3 and Cl-.

An important rule is: The stronger the acid/base, the weaker its conjugate base/acid.
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) Calculate the number of moles of sulfuric acid that is contained in 250 mL of 0.500 M sulfuric acid solution
maksim [4K]

Explanation:

According to the analysis, Molarity is amount mole per volume(1L). the amount in mole would be molarity × volume in litres.

0.500M × (250/1000)L= 0.125moles.

I hope this helps**

3 0
3 years ago
Given the equation: HCl + Na2SO4 → NaCl + H2SO4, if you start with 8 moles of hydrochloric acid, how many grams of sulfuric acid
Simora [160]

Answer:

392g sulfuric acid are produced

Explanation:

Based on the balanced equation:

2HCl + Na2SO4 → 2NaCl + H2SO4

<em>2 moles of HCl produce 1 mole of sulfuric acid</em>

<em />

To solve the problem we need to find the moles of sulfuric acid produced based on the chemical equation. Then, using its molar mass -<em>Molar mass H2SO4 = 98g/mol- </em>we can find the mass of sulfuric acid produced:

<em>Moles sulfuric acid:</em>

8mol HCl * (1mol H2SO4 / 2mol HCl) = 4 mol H2SO4

<em>Mass sulfuric acid:</em>

4mol H2SO4 * (98g / mol) =

392g sulfuric acid are produced

4 0
3 years ago
A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur
Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]       ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 30 g

m_2 = mass of water = 100 g

T_{final} = final temperature = 25°C

T_1 = initial temperature of metal = 110°C

T_2 = initial temperature of water = 20.0°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]

c_1=0.821J/g^oC

Hence, the specific heat of metal is 0.821 J/g°C

8 0
3 years ago
What is landform? please help
KATRIN_1 [288]

Answer:

A landform is a natural or artificial feature of the solid surface of the Earth or other planetary body.

Explanation:

For example, valleys, plateaus, mountains, plains, hills etc.

3 0
3 years ago
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4. Quando se obtém a potência máxima da célula, o valor indicado no amperímetro, na unidade SI, está no intervalo: (A) [3,1; 3,2
Annette [7]

Answer:i dont speak english

Explanation:

sorry

8 0
3 years ago
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