Question

In a biathlon , jackson cycled 9 miles in 3/4 of an hour in the first event. He than ran, on average, 7 miles per hour slower in the second event, which took him 1 1/2 hours. What is the distance that jackson ran in the second event ?

Answer 1

Answer:

7.5 miles

Step-by-step explanation:

Given

• In cycling,He covered 9 miles in $\frac{3}{4}$ hours,Therefore his avg cycling speed, u$=\frac{Distance}{Time} =\frac{9}{\frac{3}{4} } =12\frac{miles}{hour}$
• In second event, It took him $1\frac{1}{2} =\frac{3}{2}$hours to complete,And his avg speed,v is  7$\frac{miles}{hour}$ slower than in previous event

⇒v= u-7

v= 12-7

v=5

Distance covered in 1st event$=9miles$

Distance covered in 2nd event$=Speed\times Time= 5\times \frac{3}{2} =7.5miles$