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2 years ago

What is the energy of a photon of light with a wavelength of 3.10 × 10−7 m?

Physics

1 answer:

elena-s [515]2 years ago

3 0

E = hf = hc/λ
= (6.6 x 10^-34) × (3 × 10^8) ÷ (3.1 × 10^-7)
=6.138 × 10^-32 J

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What is the force needed to accelerate a 10 kg object at 2 m/s??

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Answer:

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Explanation:

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3 years ago

A small ball with mass 2.50 kg is mounted on one end of a rod 0.750 m long and of negligible mass. The system rotates in a horiz

alina1380 [7]

Answer:

1.40625 kg-m^2

Explanation:

Supposing we have to calculate rotational moment of inertia

Given:

Mass of the ball m= 2.50 kg

Length of the rod, L= 0.78 m

The system rotates in a horizontal circle about the other end of the rod

The constant angular velocity of the system, ω= 5010 rev/min

The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less

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3 0

3 years ago

A centrifuge has an angular velocity of 3,000 rpm, what is the acceleration (in unit of the earth gravity) at a point with a rad

Anna71 [15]

Answer:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

Explanation:

Let suppose that centrifuge is rotating at constant angular speed, which means that resultant acceleration is equal to radial acceleration at given radius, whose formula is:

$a_{r} = \omega^{2}\cdot R$

Where:

$\omega$ - Angular speed, measured in radians per second.

$R$ - Radius of rotation, measured in meters.

The angular speed is first determined:

$\omega = \frac{\pi}{30}\cdot \dot n$

Where $\dot n$ is the angular speed, measured in revolutions per minute.

If $\dot n = 3000\,rpm$ , the angular speed measured in radians per second is:

$\omega = \frac{\pi}{30}\cdot (3000\,rpm)$

$\omega \approx 314.159\,\frac{rad}{s}$

Now, if $\omega = 314.159\,\frac{rad}{s}$ and $R = 0.1\,m$ , the resultant acceleration is then:

$a_{r} = \left(314.159\,\frac{rad}{s} \right)^{2}\cdot (0.1\,m)$

$a_{r} = 9869.588\,\frac{m}{s^{2}}$

If gravitational acceleration is equal to 9.807 meters per square second, then the radial acceleration is equivalent to 1006.382 times the gravitational acceleration. That is:

$a_{r} = 1006.382g \,\frac{m}{s^{2}}$

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2 years ago