What is the energy of a photon of light with a wavelength of 3.10 × 10−7 m?

Match each characteristic with the type of wave it corresponds to. Longitudinal waves Transverse waves The direction the wave tr

zubka84 [21]

Answer:The direction the wave travels is parallel to the displacement of the medium.LW.

Electromagnetic waves are an example of this type of wave. TW

Sound waves are an example of this type of wave.LW

Ir the wave propagates in the x‑direction, the medium is also disturbed in the x‑direction. LW

If the wave propagates in the x‑direction, the medium is disturbed in the y‑ and/or z‑direction. TW

The direction the wave travels is perpendicular to the displacement of the medium.TW

Explanación:

the main difference of Transversal AND Longitudinal waves (TW AND LW) is that the disturbation direction in the media with respect to the travel direction is well different for both cases. For TW the perturbation oscilatiew perpendicular to propagation direction of the wave.

In constrant for LW the disturbation oscilates in the same direction as the wave is propagating.

3 0

3 years ago

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The acceleration of a particle moving along a straight line is given by a = −kt2 m/s2 where k is a constant and time t is in sec

RSB [31]

Answer:

$X - Xo = 54m$

k = 1/18

Explanation:

Data:

a = -k $t^{2}$ $\frac{m}{s^{2} }$

to = 0s Vo = 12m/s

t = 6s the particle chage it's moviment, so v = 0 m/s

We know that acceleration is the derivative of velocity related to time:

$a = \frac{dV}{dT}$

rearranging...

$a*dT = dV$

Then, we must integrate both sides:

$\int\limits^f_i {dV} \, dV =-k \int\limits^f_i {t^{2} } \, dT$

$V - Vo = -k\frac{t^{3} }{3}$

V = 0 because the exercise says that the car change it's direction:

$0 - 12 = -k\frac{6^{3} }{3}$

k = 1/6

In order to find X - Xo we must integer v*dT = dX

$V - Vo = -k\frac{t^{3} }{3}$

so...

$(Vo -k\frac{t^{3} }{3})dT = dX$

$\int\limits^f_i {dX} \, dX = \int\limits^f_i {Vo -k\frac{t^{3} }{3} } \, dT$

integrating...

$X - Xo = Vot -k\frac{t^{4} }{12}$

$X - Xo = 12*6 -\frac{1}{6}* \frac{6^{4} }{12}$

X - Xo = 54m

5 0

3 years ago

In a closed system, the loss of momentum of one object ________ the gain in momentum of another object.

Virty [35]

In a closed system, the loss of momentum of one object is same as________ the gain in momentum of another object

according to law of conservation of momentum, total momentum before and after collision in a closed system in absence of any net external force, remains conserved . that is

total momentum before collision = total momentum after collision

P₁ + P₂ = P'₁ + P'₂

where P₁ and P₂ are momentum before collision for object 1 and object 2 respectively.

P'₁ - P₁ = - (P'₂ - P₂)

so clearly gain in momentum of one object is same as the loss of momentum of other object

8 0

3 years ago

Describe different types of force in nature at least five

sineoko [7]

Weathering, Erosion, deposition, acid rain, precipitation

Explanation:

3 0

3 years ago

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A major difference between radio waves, visible light, and gamma rays is the ____ of the photons, which results in the different

olga2289 [7]

The sentence can be completed as follows:
"A major difference between radio waves, visible light, and gamma rays is the energy of the photons, which results in the different photon frequencies and wavelengths."

In fact, gamma rays have greater energy than visible light and visible light has greater energy than radio waves. The energy E of a photon is related to its frequency, f, by
 $E=hf$
where h is the Planck constant. We see from this formula that the higher the frequency, the greater the energy. Instead, the wavelength is inversely proportional to the frequency:
 $\lambda= \frac{c}{f}$
where c is the speed of light. Since the frequency is directly proportional to the energy, this means that the wavelength is inversely proportional to the energy.

8 0

3 years ago

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