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uysha [10]
2 years ago
6

The surface of an incline is coated with an experimental substance that is intended to reduce the frictional force between a blo

ck and the
surface of the incline. A 2 kg block is placed at the top of the incline at a height of 1.8 m, as shown in the figure. After the block is released
from rest, the block slides down the incline and a motion detector at the bottom of the incline measures the block's speed as 5.8 after the
block is no longer on the incline. Which of the following claims is correct about the experimental substance?
The experimental substance reduced all the frictional force because all the gravitational potential energy of the Earth-block
system at the top of the incline was converted into the kinetic energy of the block at the bottom of the incline.
The experimental substance did not reduce all the frictional force because some of the gravitational potential energy of the
Earth-block system at the top of the incline was converted into nonmechanical energy
с
The effectiveness of the experimental substance cannot be determined because the speed of the block at the bottom of the
inline, as measured by the motion detector, indicates that the block has more energy at this location than the Earth-block
system had at the top of the incline.
D
The effectiveness of the experimental substance cannot be determined without knowing the magnitude of the frictional
force between the block and the incline before and after the experimental substance was applied to the incline.
Lo

Physics
2 answers:
ankoles [38]2 years ago
6 0

Answer:

b

Explanation:

nikklg [1K]2 years ago
4 0

Answer:

粗糙錯愕額外此時自由KK預約為我

Explanation:

因為嗚嗚嗚粗糙此次四月蘇澳碩果僅存有一位我也在鶯鶯燕燕

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A weather balloon has a volume of 90.0 l when it is released from sea level. What
frozen [14]

The final atmospheric pressure is 5.19\cdot 10^4 Pa

Explanation:

Assuming that the temperature of the air does not change, we can use Boyle's law, which states that for a gas kept at constant temperature, the pressure of the gas is inversely proportional to its volume. In formula,

pV=const.

where

p is the gas pressure

V is the volume

The equation can also be rewritten as

p_1 V_1 = p_2 V_2

where in our problem we have:

p_1= 1.03\cdot 10^5 Pa is the initial pressure (the atmospheric pressure at sea level)

V_1 = 90.0 L is the initial volume

p_2 is the final pressure

V_2 = 175.0 L is the final volume

Solving the equation for p2, we find the final pressure:

p_2 = \frac{p_1 V_1}{V_2}=\frac{(1.01\cdot 10^5)(90.0)}{175.0}=5.19\cdot 10^4 Pa

Learn more about ideal gases:

brainly.com/question/9321544

brainly.com/question/7316997

brainly.com/question/3658563

#LearnwithBrainly

3 0
2 years ago
Which of these cultures did NOT make major contributions to astronomy?
Svetlanka [38]
I can't particularly place what Icelandic contributed.

But every  other culture contributed majorly.

So I would go for option b.
6 0
2 years ago
What is the hang time when the person moves 6 m horizontally during a 1.25 m high jump?
AlekseyPX

Answer:

1 sec

Explanation:

Horizontal distance (x) = 6m

Vertical distance (y) = 1.25m

Hang time is the duration the object is in the air before it reaches maximum height.

The time of free fall is given by

t = √2y/g

g = acceleration due to gravity

t = √(2*1.25)/9.8

t = √2.5/9.8

t = 0.5secs

Hang time = 2*0.5

= 1 sec

3 0
3 years ago
The position of a particle moving along the x axis varies in time according to the expression x = 4t 2, where x is in meters and
Pie

Answer:

a) X = 17.64 m

b) X = 17.64 + 4∆t^2 + 16.8∆t

c) Velocity = lim(∆t→0)⁡〖∆X/∆t〗 = 16.8 m/s

Explanation:

a) The position at t = 2.10s is:  

                 X = 4t^2

                 X = 4(2.10)^2

                 X = 17.64 m

b) The position at t = 2.10 + ∆t s  will be:

                 X = 4(2.10 + ∆t)^2

                 X = 17.64 + 4∆t^2 + 16.8∆t  m

c) ∆X is the difference between position at t = 2.10s and t = 2.10 + ∆t so,

                 ∆X= 4∆t^2 + 16.8∆t

Divide by ∆t on both sides:  

                ∆X/∆t =  4∆t + 16.8

 Taking the limit as ∆t approaches to zero we get:  

              Velocity =lim(∆t→0)⁡〖∆X/∆t〗 = 4(0) + 16.8

              Velocity = 16.8 m/s

 

8 0
2 years ago
Read 2 more answers
Gravitational potential energy is a form of potential energy
Gre4nikov [31]
True because it has "falling" ability
5 0
3 years ago
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