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Nadusha1986 [10]
3 years ago
11

Both artists and scientists contribute to our understanding of the world around us. Identify the ways that

Chemistry
2 answers:
Alchen [17]3 years ago
4 0

Answer:

A B and D is correct

Explanation:

LUCKY_DIMON [66]3 years ago
3 0

Answer:

I deeply believe that it would be options 1, 2, and 4? Sorry if i'm wrong and good luck!

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Equation for the for formation of ethanoic acid<br>​
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2 C4H10 + 5 O2 → 4 CH3CO2H + 2 H2O.

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Light naphtha components are readily oxidized by oxygen or even air to give peroxides, which decompose to produce acetic acid according to the chemical equation, illustrated with butane .

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A 15.0 g piece of graphite is heated to 100.0°C and placed in a calorimeter. The
LenKa [72]

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0.714Jg^-10C^-1.

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How to balance this equation NH4OH+H3PO4=(NH4)3PO4+H2O with explainatio please ​
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3 NH4OH (l) + H3PO4 (aq) → (NH4)3PO4 (aq) + 3 H2O (l)

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Does the absolute reference system consider a fixed reference system of reference?
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The definition of an absolute reference frame would be that fixed reference frame that every observer would rest at all times in his/her state of motion.

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6 0
2 years ago
Assuming that a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, determine how many kg of co2 are prod
sleet_krkn [62]

Answer: -

If a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

Explanation: -

Density of the gasoline = 0.77 kg / liter

Volume of the tank containing the gasoline = 80 liter.

Mass of gasoline produced from each tank

= Volume of the tank containing the gasoline x Density of the gasoline

= \frac{0.77 kg}{1 liter} x 80 liter

= 61.6 kg

Chemical formula of gasoline = C₈H₁₈

Molar mass of gasoline C₈H₁₈ = 12 x 8 + 1 x 18 = 114 g/ mol

Number of moles of C₈H₁₈ = \frac{61.6 g}{114 g} x 1 mol

= 0.54 mol of C₈H₁₈

The chemical equation for the burning of gasoline is

2 C₈H₁₈ + 25 O₂ → 16 CO₂ + 18 H₂O

From the balanced equation we see

2 mol of C₈H₁₈ gives 16 mol of CO₂

0.54 mol of C₈H₁₈ gives \frac{16 mol CO2 x 0.54 mol C8H18}{2 mol C8H18} mol of CO₂

= 4.32 mol of CO₂

Molar mass of CO₂ = 12 x 1 + 16 x 3 =60 g / mol

Mass of CO₂ = Molar mass of CO₂ x Number of moles of CO₂

=\frac{60g x 4.32 mol}{1 mol}

= 259.2 g

= \frac{259.2}{1000}

= 0.259 Kg

= 0.26 kg rounded off to 2 significant figures.

Thus if a tank of gasoline contains 80 liters and that its density is 0.77 kg/liter, 0.26 kg of CO₂ are produced for each tank of gasoline burned.

4 0
3 years ago
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