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Ber [7]
3 years ago
5

0.750mol of gas are stored in a tank at a pressure of 275kpa and a temperature of 0.00 degrees * C What is the volume of the tan

k?
Chemistry
1 answer:
nordsb [41]3 years ago
4 0

Answer:

The volume on the tank is 6, 20 L

Explanation:

We use the formula PV=nRT. We convert the units of pressure in kPa into atm and temperature in Celsius into Kelvin:

0°C=273K

101,325kPa---1 atm

275kPa --------x=(275kPax 1 atm)/101,325kPa= 2,71 atm

PV=nRT --> V=nRT/P

V= 0,750 mol x 0,082 l atm /K mol x 273 K/ 2, 71 atm= <em>6, 20 L</em>

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Why is specific activity used as a measurement of enzyme purity, but the turnover number cannot be used for this purpose?
Lelechka [254]

Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

4 0
3 years ago
Pure nitrogen (N2) and pure hydrogen (H2) are fed to a mixer. The product stream has 40.0% mole nitrogen and the balance hydroge
LuckyWell [14K]

Explanation:

The given data is as follows.

        Mass flow rate of mixture = 1368 kg/hr

      N_{2} in feed = 40 mole%

This means that H_{2} in feed = (100 - 40)% = 60%

We assume that there are 100 total moles/hr of gas (N_{2} + H_{2}) in feed stream.

Hence, calculate the total mass flow rate as follows.

           40 moles/hr of N_{2}/hr (28 g/mol of N_{2}) + 60 moles/hr of H_{2}/hr (2 g/mol of H_{2})

                  40 \times 28 g/hr + 60 \times 2 g/hr    

                  = 1120 g/hr + 120 g/hr

                  = 1240 g/hr

                  = \frac{1240}{1000}              (as 1 kg = 1000 g)

                  = 1.240 kg/hr

Now, we will calculate mol/hr in the actual feed stream as follows.

                 \frac{100 mol/hr}{1.240 kg/hr} \times 1368 kg/hr

                   = 110322.58 moles/hr

It is given that amount of nitrogen present in the feed stream is 40%. Hence, calculate the flow of N_{2} into the reactor as follows.

                       0.4 \times 110322.58 moles/hr

                      = 44129.03 mol/hr

As 1 mole of nitrogen has 28 g/mol of mass or 0.028 kg.

Therefore, calculate the rate flow of N_{2} into the reactor as follows.

                       0.028 kg \times 44129.03 mol/hr

                         = 1235.612 kg/hr

Thus, we can conclude that the the feed rate of pure nitrogen to the mixer is 1235.612 kg/hr.

3 0
3 years ago
PLEASE ANSWER. True or false: An inference explains an observation.
Elodia [21]

Answer:

true

Explanation:

8 0
3 years ago
Read 2 more answers
What is the mass of 7 moles of Nitrogen?
Igoryamba

Hey there!

Molar mass of nitrogen is 14.007 g.

We have 7 moles.

Multiply 7 by 14.007.

7 x 14.007 = 98.049

7 moles of nitrogen has a mass of 98.049 grams.

Hope this helps!

8 0
3 years ago
A bottle of acetone (fingernail polish remover) contains 55.0 mL of acetone. If the acetone has a mass of 43.5 g, what is the de
mihalych1998 [28]
If you were to use the formula to find density which is D=M/V and plug in your numbers M which stands for mass and and plug in your numbers for V which what’s for Volume and should be a number in mL and then divide them you should get your answer. So 43.5g divided by 55.0mL and your density would = 0.79g/mL
5 0
3 years ago
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