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lions [1.4K]
3 years ago
8

The final temperature and pressure in a container is 234K at 210 kPa.

Chemistry
1 answer:
andre [41]3 years ago
5 0

Answer:

Initial pressure = 157 kpa (Approx)

Explanation:

Given:

final temperature = 234 K

final pressure = 210 kpa

Initial temperature = 175 K

Find:

Initial pressure

Computation:

Initial pressure / Initial temperature = final pressure / final temperature

Initial pressure / 175 = 210 / 234

Initial pressure = 157 kpa (Approx)

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A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
3 years ago
The concentrated sulfuric acid we use in the laboratory is 98.0% sulfuric acid by weight. Calculate the molality and molarity of
timama [110]

Answer : The molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

Solution : Given,

Density of solution = 1.83g/cm^3=1.83g/ml

Molar mass of sulfuric acid (solute) = 98.079 g/mole

98.0 % sulfuric acid by mass means that 98.0 gram of sulfuric acid is present in 100 g of solution.

Mass of sulfuric acid (solute) = 98.0 g

Mass of solution = 100 g

Mass of solvent = Mass of solution - Mass of solute = 100 - 98.0 = 2 g

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}=\frac{100g}{1.83g/ml}=54.64ml

Now we have to calculate the molarity of solution.

Molarity=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{volume of solution}}=\frac{98.0g\times 1000}{98.079g/mole\times 54.64ml}=18.29mole/L

Now we have to calculate the molality of the solution.

Molality=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent}}=\frac{98.0g\times 1000}{98.079g/mole\times 2g}=499.59mole/Kg

Therefore, the molarity and molality of the solution is, 18.29 mole/L and 499.59 mole/Kg respectively.

7 0
3 years ago
can someone please help me with this question for chemistry. What is the number of moles in 1216 g Sr3(PO4)2? the 3,4, and 2 and
Alisiya [41]
2.68 mol should be the answer
8 0
3 years ago
Electrons are attracted to ________________. protons other electrons neutrons all the particles
rjkz [21]
Protons .because electron has negative charge and proton has positive charge.
6 0
3 years ago
Why neutron doesn't contain any charge?​
zhuklara [117]

Answer:

Neutron does not contain any charge because the charge of the quarks that made up the neutron balances each other out.

Hope it helps.

7 0
2 years ago
Read 2 more answers
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