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Romashka-Z-Leto [24]
3 years ago
9

Determine the possible traits of the calves if:

Chemistry
1 answer:
White raven [17]3 years ago
7 0

Answer:

1. All red calves i.e. RR

2. All roan calves i.e RW

3. 2 red calves (RR) and two roan calves (RW)

Explanation:

According to this question, a gene coding for fur colour in cattle is involved. Red alleles (R) and white alleles (W) are co-dominant to produce a roan cattle (RW). The possible traits of the following crosses are (see attached punnet square):

1) A red bull (RR) is mated to a red (RR) cow: All red calves i.e. RR

2) A red (RR) bullis mated with white (WW) cow: All roan calves i.e RW

3) A roan bull (RW) is mated with red (RR) cow: 2 red calves (RR) and two roan calves (RW).

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The chemical equation shows only the reactants and one product. How many H atoms must be present in the second product that is f
cestrela7 [59]

Answer: In chemical equations, the number of atoms of each element in the reactants must be the same as the number of atoms of each element in the products. If we count the number of hydrogen atoms in the reactants and products, we find two hydrogen atoms.

4 0
3 years ago
How many grams are in 1.3 x 1024 atoms of hydrogen?
olga2289 [7]

Answer: 4.32g

Explanation:

MM of H2 = 1 x 2 = 2g/mol

2g of H2 contains 6.02x10^23 atoms.

Therefore Xg of H2 will contain 1.3 x 1024 atoms i.e

Xg of H2 = (2 x 1.3 x 1024) / 6.02x10^23 = 4.32g

7 0
3 years ago
Why does a year consist of 365 days and a day of 24 hours?
poizon [28]
<span>A year, 365 days, is the time it takes for the Earth to travel around the Sun. A day, 24 hours, is the time it takes for the Earth to spin around once on its axis.</span>
5 0
3 years ago
Read 2 more answers
Beverly and Carl are in a race. Their graphs show the data.
Nikitich [7]

Given the data, the correct statement is

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

<h3>What is acceleration? </h3>

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

  • a is the acceleration
  • v is the final velocity
  • u is the initial velocity
  • t is the time

<h3>How to determine the initial acceleration of Beverly</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 15 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (15 – 0) / 10

a₁ = 1.5 m/s²

<h3>How to determine the final acceleration of Beverly</h3>
  • Initial velocity (u) = 15 m/s
  • Final velocity (v) = 35 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (35 – 15) / 40

a₂ = 0.5 m/s²

<h3>How to determine the initial acceleration of Carl</h3>
  • Initial velocity (u) = 0 m/s
  • Final velocity (v) = 10 m/s
  • Time (t) = 10 s
  • Initial acceleration (a₁) =?

a₁ = (v – u) / t

a₁ = (10 – 0) / 10

a₁ = 1 m/s²

<h3>How to determine the final acceleration of Carl</h3>
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 30 m/s
  • Time (t) = 50 - 10 = 40 s
  • Final acceleration (a₂) =?

a₂ = (v – u) / t

a₂ = (30 – 10) / 40

a₂ = 0.5 m/s²

SUMMARY

  • Initial acceleration of Beverly = 1.5 m/s²
  • Final acceleration of Beverly = 0.5 m/s²
  • Initial acceleration of Carl = 1 m/s²
  • Final acceleration of Carl = 0.5 m/s²

From the above calculations, we can see that Beverly's initial acceleration is higher than that of Carl's and their final acceleration is the same.

Therefore, the correct answer to the question is:

Even though for a majority of the race they accelerated at the same rate, Beverly won because her initial acceleration was greater than Carl’s

Complete question

See attached photo

Learn more about acceleration:

brainly.com/question/491732

#SPJ1

8 0
2 years ago
Consider the following reactions: 1. 2 SO3(g) ⇄ 2 SO2(g) + O2(g) K 1 = 2.3 × 10-7 2. 2 NO3(g) ⇄ 2 NO2(g) + O2 (g) K 2 = 1.4× 10-
juin [17]

Answer:

K =78

Explanation:

Step 1: Data given

2SO3(g) <--> 2SO2(g) + O2(g)  kc = 2.3 x 10^-7

2NO3(g) <--> 2NO2(g) + )2(g)   kc = 1.4 x 10^-3

Step 2: Calculate K

Lets write out the two reactions in the proper order and look at how they sum together:

2 SO2(g) + O2(g)  <---> 2 SO3(g)   (1)

2NO3(g) <---> 2 NO2(g)  + O2(g)    (2)

The two reactions as now written give us the correct reactants and products on the correct sides of the reaction arrow.

Since we have O2 as both a reactant and a product, we can cancel O2 and are not part of the final overall reaction equation.

Koverall =  Kc1  * Kc2

Because we reversed reaction number 1 this affects its Kc via the following:

Krev  =  1/Kfwd.  

We then replace Kc1 with its value for the reverse direction.

So  Koverall now =   (1/Kfwd) * Kc2

The sum of the two reactions above gives us:

2 SO2(g) +  2 NO3(g)  <--->  2 SO3(g)  + 2 NO(g)  

The problem states to give the K value for the reaction where all the numbers in front of the molecules are (1), and we have (2)'s.  So basically  if we multiply the whole reaction by 1/2 we'll get the final overall equation we want.

1/2  ( 2 SO2(g)  + 2 NO3(g)  <----> 2 SO3(g)  + 2 NO(g) )

 

So Kfinal =  (Koverall)^1/2    

K =  ( 1/Kfwd  *  Kc2)^1/2

K =  ( [1 / 2.3 * 10^-7]   *  1.4 * 10^-3)^1/2

K =78

3 0
3 years ago
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