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konstantin123 [22]

3 years ago

11

To find time, t, the age of the universe, you must first isolate the variable t. Rewrite the velocity equation v = d / t so that

you are solving for time.

1 answer:

Alex17521 [72]3 years ago

4 0

Answer:

t = d/v

Explanation:

All you have to do is the inverse operation so that you multiply by "t" and it will be on the side with the "v" then you divide the v and it will be under the "d" so time = distance/ velocity (speed)

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How many electrons can be held in the second orbital (closest to the nucleus)

anzhelika [568]

A valence electron structure would be like this 1s^2 2s^2 2p^6 etc
1s^2 would be 2, 2s^2 would be 4, 2p^6 would be 12 and so on and so forth.

6 0

3 years ago

Read 2 more answers

a perfect cube of aluminum metal was found to weigh 20.00 g. the density of aluminum is 2.70 g/ml . what is the dimension of the

Rudiy27

So Volume = to mass / density, right?

20 / 2,70 g/ml = 7.407

The cube's dimension is 7,407 ml

8 0

4 years ago

You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially

nika2105 [10]

Answer :

(a) The heat released by the metal is -312.48 J

(b) The specific heat of the metal is $0.0944J/g^oC$

Explanation :

<u>For part A :</u>

Heat released by the metal = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the metal

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $51.5J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 50.0 g

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-22.0=1.2^oC$

Now put all the given values in the above formula, we get:

$q=[(51.5J/^oC\times 1.2^oC)+(50.0g\times 4.184J/g^oC\times 1.2^oC)]$

$q=312.48J$

Thus, the heat released by the metal is -312.48 J

<u>For part B :</u>

$q=m\times c\times \Delta T$

q = heat released by the metal = -312.48 J

m = mass of metal = 43.1 g

c = specific heat of metal = ?

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-100=76.8^oC$

Now put all the given values in the above formula, we get:

$-312.48J=43.1g\times c\times 76.8^oC$

$c=0.0944J/g^oC$

Thus, the specific heat of the metal is $0.0944J/g^oC$

8 0

4 years ago

A student decreases the temperature of a 556 c m cubed balloon from 278 K to 231 K. Assuming constant pressure, what should the

a_sh-v [17]

Answer:

The new volume of the balloon be $462\ cm^3$ .

Explanation:

We have,

Initial volume is 556 cm ³

The temperature of the balloon decreases from 278 K to 231 K.

We need to find the new volume of the balloon if the pressure is constant.

The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.

$V\propto T$ , P is constant

$\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{556\times 231}{278}\\\\V_2=462\ cm^3$

So, the new volume of the balloon be $462\ cm^3$ .

3 0

3 years ago

How many moles are 32 grams of O2?

Kaylis [27]

The formula for determining the moles of a compound is grams (g) divided by molecular weight (MW), or moles = g / MW. The molecular formula of oxygen gas is O₂, and because each oxygen atom possesses an atomic weight of 16.00 grams per mole (g/mol) (this value is found on the Periodic Table), the MW of oxygen gas is 32.00 g/mol. Therefore, 32 g of oxygen gas represent (32 g) / (32.00 g/mol) = 1.0 moles of O₂.<span>Source(s):
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6 0

3 years ago