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konstantin123 [22]
3 years ago
11

To find time, t, the age of the universe, you must first isolate the variable t. Rewrite the velocity equation v = d / t so that

you are solving for time.
Chemistry
1 answer:
Alex17521 [72]3 years ago
4 0

Answer:

t = d/v

Explanation:

All you have to do is the inverse operation so that you multiply by "t" and it will be on the side with the "v" then you divide the v and it will be under the "d" so time = distance/ velocity (speed)

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Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these were decomposed the sulfur dioxide produce
Zinaida [17]

Answer : The mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

Explanation : Given,

Mass of oxygen in sulfur dioxide = 3.49 g

Mass of sulfur in sulfur dioxide = 3.50 g

Mass of oxygen in sulfur trioxide = 9.00 g

Mass of sulfur in sulfur trioxide = 6.00 g

Now we have to calculate the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide.

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur dioxide = \frac{3.49}{3.50}=0.997g

and,

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{\text{Mass of oxygen}}{\text{Mass of sulfur}}

Mass of oxygen per gram of sulfur for sulfur trioxide = \frac{9.00}{6.00}=1.5g

Thus, the mass of oxygen per gram of sulfur for sulfur dioxide and sulfur trioxide is, 0.997 g and 1.5 g respectively.

8 0
3 years ago
Write the net ionic equation:. . A solution of diamminesilver(I) chloride is treated with dilute nitric acid
zimovet [89]
<span> Ag(NH3)2Cl + 3HNO3 = AgNO3 +2NH4NO3 + HCl </span>
<span>or
 Ag(NH3)2Cl + HNO3 = Ag(NH3)2NO3 + HCl  this the complete balanced equation
now remove spectator ions to get net ionic equation
so 
</span>
<span> 2H+ + 2NO3- + [Ag(NH3)2]+ Cl- -> AgCl + 2NH4+ + 2NO3-  2NO3-  2H+  [Ag(NH3)2]+ + Cl- -> AgCl + 2NH4+
</span>hope it helps
5 0
3 years ago
Read 2 more answers
Li + HNO3 &gt; LiNO3 + H2 how do I balance it? Show work pls
azamat

Answer: The balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

Explanation:

The given reaction equation is as follows.

Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}

Number of atoms present on reactant side are as follows.

  • Li = 1
  • H = 1
  • NO_{3} = 1

Number of atoms present on product side are as follows.

  • Li = 1
  • H = 2
  • NO_{3} = 1

To balance this equation, multiply Li by 2 and HNO_{3} by 2 on reactant side. Also, multiply LiNO_{3} by 2 on product side.

Hence, the equation can be rewritten as follows.

2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}

Now, number of atoms present on reactant side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

Number of atoms present on product side are as follows.

  • Li = 2
  • H = 2
  • NO_{3} = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is 2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}.

3 0
3 years ago
A missile is flying at a speed of 125 m/s. If the missile has a mass of 125 kg, what’s its kinetic energy?
LenKa [72]

976,563 is the answer I got to your question

5 0
3 years ago
Read 2 more answers
the radioisotope radon-222 has a half-life of 3.8 days. how much of a 65-g sample of radon-222 would be left after approximately
MariettaO [177]
Use the 1st order decay equation 
<span><span>Cfinal</span>=<span>Cinitial</span><span>e<span>−kt</span></span></span> 
by filling in and doing the math you will get:

<span> </span><span>Cfinal</span><span> = 1.11 grams Rn-222 after 23 days. 
 
hope this helps 

</span>
7 0
3 years ago
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