What is the specific heat of a substance if 60.0 J are required to increase the temperature of 6 grams
1 answer:
Using the specific heat capacity formula:
q = mc ∆ t
60.0 J = (6g)(x)(11*C)
x = 0.9 J/g*C
Aluminum
You might be interested in
Answer:
sorry but i'm not that smart
Floats or sinks Because of its mass
The answer should be "broad and fuzzy"
Answer:
C
Explanation:
the enthalpy of reaction is independent of the reaction path
Answer:
c
Explanation:
c first quarter waxing half moon
