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kaheart [24]
3 years ago
13

What is the specific heat of a substance if 60.0 J are required to increase the temperature of 6 grams

Chemistry
1 answer:
Alika [10]3 years ago
3 0
Using the specific heat capacity formula:

q = mc ∆ t
60.0 J = (6g)(x)(11*C)
x = 0.9 J/g*C

Aluminum
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Help here are the choices
Murljashka [212]
PH Answer/definition - A value from 0 to 14 that is used to specify how acidic or basically a compound of when it is dissolved in water.

Ions Answer/definition - An atom or molecule that has a positive of negative charge.

Acid Answer/definition - A compound that increases the hydroxide ions (OH-) when it is dissolved in a solution. (Arrhenius Acid)

Base Answer/definition - A compound that increases hydrogen ions (H+) when it is dissolved in a solution.


Hope this helps you out :)))
5 0
3 years ago
Read 2 more answers
1. ¿Cuál de los factores se deben emplear para convertir: a. ¿Número de moles de cloro en número de moles de NaCl? b. Moles de s
Alex

Answer:

Número de moles de cloro en número de moles de NaCl

Explanation:

espero que si sea la correcta

7 0
2 years ago
What is a percent volume of ethanol c2h60 in the final solution when 85 ml of it is diluted to a volume?
Ilya [14]
34% I believe

Hope this helps!
STSN
3 0
3 years ago
Hi, someone knows how to balance the following equation, and if you can thank you if you can explain how that is done:
kari74 [83]
To begin with, the equation given is not correct.
Correct equation is : CaCO3 + HCl ---> CaCl2 + H2O + CO2
It's CaCl2 not CaCl because Ca has a valency of 2 

    LHS                          RHS
CaCO3 + HCl ---> CaCl2 + H2O + CO2
First of all, to balance the equation you must look at the number of atoms on each side of the equation. 
we have 2 H on the RHS and 1 H on the LHS. So, we put a 2 on the LHS

CaCO3 + 2HCl ---> CaCl2 + H2O + CO2
Check for the LHS: 1 Ca, 1 C, 3 O, 2 H & 2 Cl on the LHS
Now check for the RHS: 1 Ca, 2 Cl, 2 H, 1 C & 3 O

Hope it helped!
7 0
3 years ago
Suppose you start with one liter of vinegar and repeatedly remove 0.08 L, replace with water, mix, and repeat. a. Find a formula
Bumek [7]

Answer:

0.92^n

Explanation:

Given that :

Initial amount of vinegar = 1 Litre

Number of litres removed repeatedly = 0.08 Litre

Since the amount removed each time is constant, then ;

Initial % = 100% = 100/100 = 1

. Using the relation :

Amount of vinegar in mixture :

Initial * (1 - amount removed / initial amount)^n

n = number of times repeated

1 * (1 - 0.08/1)^n

1 * (1 - 0.08)^n

1 * 0.92^n

Hence,

For nth removal,

Concentration will be :

0.92^n ; for n ≥ 1

7 0
2 years ago
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