Complete the square of X² +8x+15=0

Sum or difference 7/8 + 1/3

Alex

Answer:

Sum. If the problem asks to add the two fractions, the result is:

$\frac{29}{24}$

Step-by-step explanation:

If you mean to simply state whether this is a sum or a difference, it's a sum.

This is because of the + sign present between the two fractions which indicates it's an addition.

If it was a - it would indicate it was a subtraction problem (or difference)

In order to solve this, we will have to get a common denominator on both fractions. In this case, to do this, we can multiply each denominator to the other fraction, such that:

$3(\frac{7}{8}) + 8(\frac{1}{3})\\\\\frac{21}{24} + \frac{8}{24}\\\\\frac{21 + 8}{24}\\\\\frac{29}{24}\\$

This can't be simplified further, but can be represented in decimal form as 1.20833.

Good luck!

6 0

3 years ago

the math magician Archimedes believed that pi was between 3 1/7 and 3 10/71. Was Archimedes correct? explain

Rufina [12.5K]

A Brief History of πPi has been known for almost 4000 years—but even if we calculated the number of seconds in those 4000 years and calculated pi to that number of places, we would still only be approximating its actual value. Here’s a brief history of finding pi:The ancient Babylonians calculated the area of a circle by taking 3 times the square of its radius, which gave a value of pi = 3. One Babylonian tablet (ca. 1900–1680 BC) indicates a value of 3.125 for pi, which is a closer approximation.The Rhind Papyrus (ca.1650 BC) gives us insight into the mathematics of ancient Egypt. The Egyptians calculated the area of a circle by a formula that gave the approximate value of 3.1605 for pi.The first calculation of pi was done by Archimedes of Syracuse (287–212 BC), one of the greatest mathematicians of the ancient world. Archimedes approximated the area of a circle by using the Pythagorean Theorem to find the areas of two regular polygons: the polygon inscribed within the circle and the polygon within which the circle was circumscribed. Since the actual area of the circle lies between the areas of the inscribed and circumscribed polygons, the areas of the polygons gave upper and lower bounds for the area of the circle. Archimedes knew that he had not found the value of pi but only an approximation within those limits. In this way, Archimedes showed that pi is between 3 1/7 and 3 10/71.A similar approach was used by Zu Chongzhi (429–501), a brilliant Chinese mathematician and astronomer. Zu Chongzhi would not have been familiar with Archimedes’ method—but because his book has been lost, little is known of his work. He calculated the value of the ratio of the circumference of a circle to its diameter to be 355/113. To compute this accuracy for pi, he must have started with an inscribed regular 24,576-gon and performed lengthy calculations involving hundreds of square roots carried out to 9 decimal places.

Mathematicians began using the Greek letter π in the 1700s. Introduced by William Jones in 1706, use of the symbol was popularized by Leonhard Euler, who adopted it in 1737.

An Eighteenth century French mathematician named Georges Buffon devised a way to calculate pi based on probability. You can try it yourself at the Exploratorium's Pi Toss exhibit.

4 0

3 years ago

What is the absolute value of −5?

natima [27]

Answer:

5

Step-by-step explanation:

always 5

6 0

3 years ago

Read 2 more answers

Which set or sets does the number 15 belong to?

BlackZzzverrR [31]

It belongs to rational,whole,integer,real.

Hope this helped :)

3 0

3 years ago

The weights of adult male beagles are normally distributed, with a mean of 25 pounds and a standard deviation of 4 pounds.

Andrews [41]

Answer:

A) 8

Step-by-step explanation:

Mean weight = u = 25 pounds

Standard Deviation = $\sigma$ = 4 pounds

We have to find how many beagles out of 75 will weigh more than 30. Since the data is normally distributed, we can use z score to find this value. First we will what is the percentage(probability) of a randomly selected beagle to weigh more than x = 30 pounds, using this percentage we can then find our answer.

The formula for z score is:

$z=\frac{x-u}{\sigma}$

Using the values, we get:

$z=\frac{30-25}{4}=1.25$

So, P(Weight > 30) is equivalent to P(z > 1.25). Using the z table, we can write:

P(z > 1.25) = P(Weight > 30) = 0.1056

This, 0.1056 or 10.56% of the beagles are expected to weigh more than 30 pounds.

So,out of 75 beagles, 10.56% of 75 are expected to weigh more than 30 pounds.

10.56% of 75 = 0.1056 x 75 = 7.92 = 8 (rounding to nearest integer)

Therefore, out of 75 beagles 8 are expected to weigh more than 30 pounds.

6 0

3 years ago