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Oxana [17]
3 years ago
12

A closed 5.00 L container is filled with a mixture of 4.00 moles of hydrogen gas, 8.00 moles of oxygen, 12.0 moles of helium, an

d 6.00 moles of nitrogen. What is the pressure due to the oxygen in this container at a temperature of 25 °C?
Chemistry
1 answer:
rjkz [21]3 years ago
7 0

Answer:

24.44 atm

Explanation:

Considering that this gas mixture behaves like an ideal gass, and that all component gases are ideal gases, we can use:

PV=nRT

Then:

P=nRT/V

Where:

n= N° of moles

R= gas constant= 0.082 Lt*atm/K*mol

T= temperature (in Kelvin)

V = volume (in Lt)

Finally, statement says:

T = 25°C = 298 K

V = 5 Lt

n = 8 moles (for O₂)

P = [8 molx(0.082 Lt*atm/K*mol)x298 K]/5 Lt

P = 24.44 atm would be the pressure due to O₂ (partial pressure of the oxygen)

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