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svlad2 [7]
3 years ago
13

Extracting oil from shale deposits a has been initiated on a large scale in the United States and will soon surpass Canada's pro

duction. b involves removing and refining waxy hydrocarbons called kerogen. c in the United States will take place mostly in northeast states as well as in Georgia and Florida. d in the United States has been studied by the EPA and found not to endanger ground water supplies.
Chemistry
1 answer:
dalvyx [7]3 years ago
6 0

Answer:

The correct answer is;

b involves removing and refining waxy hydrocarbons called kerogen

Explanation:

Shale oil deposits are present in the United States in the Green River formation in Wyoming, Utah and Colorado and in the Devonian Oil  shales in Kentucky, Tennessee, Ohio and Indiana.

Shale oil has boosted crude oil production since 2014 and the United states  is presently one of the world's largest producers crude-oil.

Kerogen, found in oil shale is treated to produce shale oil with about 6.05 trillion barrels of oil in place globally.

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A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4
Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

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