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Alisiya [41]
3 years ago
8

*Giving Brainly with the points* Best answer gets it

Chemistry
1 answer:
Sedaia [141]3 years ago
6 0
List two uses of high density polyethylene other than those listed in the table:
HDPE plastic is also used to store bleach, baby powder, and vitamins.

Two plastics that are targeted for recycling from household waste are polyethylene terephthalate (PETE) and high density polyethylene (HDPE). One of the problems of recycling such materials is separating them. Suppose you have been hired to set up a process for separating large quantities of waste plastic that is a mixture of PETE and HDPE. Describe how you might perform this separation:
To separate PETE and HDPE plastics on an industrial scale, you could place large quantities of recycled products in a vat water so the PETE products sink while the HDPE products float.
You might be interested in
Ethanol (C2H5OH) melts at –114 °C and boils at 78 °C. The enthalpy of fusion of ethanol is 5.02 kJ/mol, and its enthalpy of vapo
alexandr1967 [171]

Answer:

First question

       Q =  36826 \  J

Second  question  

       Q =  52299.7  \  J

Explanation:

From the question we are told that

     The melting point of Ethanol is  T_m  =  -114 ^oC

      The boiling point of Ethanol is  T_b   =  78^ oC

       The enthalpy of fusion of Ethanol is F  =  5.02 \  kJ / mol = 5.02 *10^{3}\  kJ / mol

        The enthalpy of vaporization  of Ethanol is L  =  38.56  \  kJ / mol = 38.56 *10^{3} \  J / mol

         The specific heat of solid Ethanol is  c_e = 0.97 \  J/ g \cdot K

          The specific heat of liquid  Ethanol is c_l  =  2.3 \  J / g \cdot K

           The mass of the Ethanol given is  m =  35.0 \ g

Considering the first question

           The initial  temperature is T_i  =  27^oC

             The final  temperature is  T_f  =  120^oC

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       Q_1 =  m  *  c_l *  (T_b - T_i)

=>      Q_1  =  35.0   *  2.3  *  (  78 - 27)

=>      Q_1  =4106 \ J

Genially the number of moles of Ethanol given is mathematically represented as

         n  = \frac{m}{Z}

Here Z  is the molar mass of Ethanol  with value  Z =  46 g/mol

So

         n  = \frac{35}{46 }

=>      n  = 0.7609 \  mol

Generally the heat of vaporization of the Ethanol is mathematically represented as

         Q_2 = n  * L

=>        Q_2  =0.7809   *  38.56  * 10^{3}

=>        Q_2  =29339  \  J

Generally the heat required too raise the Ethanol from  its boiling point to  T_f  is  mathematically represented as

       Q_3 =  m  *  c_l *  (T_f - T_b)

=>     Q_3 =  35   *   2.3 *  (120 - 78 )

=>     Q_3 = 3381 \  J

Generally the total heat required is  

     Q =  Q_1 + Q_2 + Q_3

=>   Q =  4106    + 29339   + 3381

=>   Q =  36826 \  J

Considering the second question

           The initial  temperature is T_i  =  -120^oC

             The final  temperature is  T_f  =  120^oC

Generally the heat required too raise the Ethanol to its melting  point is mathematically represented as

       Q_1 =  m  *  c_e *  (T_m - T_i)

=>      Q_1  =  35.0   *  0.97  *  ( -114 - (- 120) )

=>      Q_1  = 203.7 \ J

Generally the heat of fusion  of the Ethanol is mathematically represented as

                 Q_2 = n  * F

=>        Q_2  =0.7809   *  5.02 *10^{3}

=>        Q_2  =3920  \  J

Generally the heat required too raise the Ethanol to its boiling point is mathematically represented as

       Q_3 =  m  *  c_l *  (T_b - T_m)

=>      Q_3  =  35.0   *  2.3  *  ( 78 - (- 114) )

=>      Q_3  =15456  \ J

Generally the heat of vaporization of the Ethanol is mathematically represented as

         Q_4 = n  * L

=>        Q_4  =0.7809   *  38.56  * 10^{3}

=>        Q_4  =29339  \  J

Generally the heat required too raise the Ethanol from  its boiling point to  T_f  is  mathematically represented as

       Q_5 =  m  *  c_l *  (T_f - T_b)

=>     Q_5 =  35   *   2.3 *  (120 - 78 )

=>     Q_5 = 3381 \  J

Generally the total heat required is  

     Q =  Q_1 + Q_2 + Q_3+Q_4 + Q_5

=>   Q =  203.7    + 3920   + 15456 +29339+3381

=>   Q =  52299.7  \  J

5 0
3 years ago
What are the most of the elements in the periodic table
vaieri [72.5K]

Answer:

Most of the elements in the periodic table are <u><em>metals</em></u>.

Hope that helps. x

5 0
2 years ago
Read 2 more answers
Which compound will have the larger rf value on a si02 tlc plate using 10 % ethyl acetate/ hexane as eluent: 3-decanone or 3-dec
Hatshy [7]

The formula of determining the R_f value is:

R_f = \frac{distance travelled by the solute}{distance travelled by the solvent}

where both the distance are measured from the common origin.

10 % ethyl acetate/ hexane means it has 10 % ethyl acetate and 90 % hexane which are non-polar in nature. Hence, the non-polar compound will travel farther in the TLC plate along with the eluent and the polar compound will travel less as they remain attracted to the polar adsorbent SiO_2.

Among 3-decanone and 3-decanol, 3-decanone will have high R_f as it is non-polar.

Among toluene and benzoic acid, toluene will have high R_f as it is non-polar.

Among cyclooctane and cyclooctanone, cyclooctane will have high R_f as it is non-polar.

7 0
3 years ago
Draw the addition product formed when one equivalent of hcl reacts with the following diene.
pashok25 [27]

Answer:

                    Major Product = 4-chloro-4-methylcyclohex-1-ene

Explanation:

                     Alkene are the class of organic compounds which contain one or more double bonds between two carbon atoms. Alkenes are considered most reactive among the unsaturated hydrocarbons and they undergo <em>addition reactions</em> due to high electron density around the double bonds.

                      In given question it is written that we are provided with one equivalent of HCl while, our compound contains two double bonds (diene) so in selected starting material the HCl will be added across (hydrohalogenation reaction) the substituted double bond because it will give a more stable carbocation (<u><em>tertiary carbocation</em></u>) during the reaction course. Hence, as shown in reaction scheme 4-chloro-4-methylcyclohex-1-ene will be the major product.

5 0
3 years ago
List the Earth names for the 30 alien elements in order of atomic number
mariarad [96]
Pfsst
bombal
chow
ddoggone
ernst
floxxit
goldy
nuutye
apstrom
logon
byyou
zapper
yazzer
highho
magnificon
oz
fratt
jeptum
quackzil
doadeer
rhaap
terriblum
sississ
urrp
vulcania
wobble
xtalt
pie
anatom
eldorado  (I think these are the answers)
6 0
3 years ago
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