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Contact [7]
3 years ago
9

1.In class, students learned that a cart will move when a force of 50 N or greater is applied. A student pushed on the cart with

a force of 10 N. The cart did not move. Why not?
2. Student A pushed on the cart with a force of 500 N. Student B pushed on the other side of the cart. The cart did not move. How much force did student B apply? Explain how you know.

3. 3. Student A pushed on the cart with a force of 400 N. Student C pushed on the other side of the cart. The cart rolled to the left. Did student C apply more, less, or the same force as student A? Explain how you know.

Yo help me this is due in 15 mins
Chemistry
1 answer:
kykrilka [37]3 years ago
7 0
1. The student didn’t push with enough force ._.
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How many moles of potassium nitrate are required to make 550 mL of a 2.1M solution?
stira [4]

Answer:

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

Explanation:

In a mixture, the chemical present in the greatest amount is called a solvent, while the other components are called solutes.

Molarity is a unit of concentration of a solution and indicates the amount of moles of solute that appear dissolved in each liter of the mixture. In other words, the Molarity (M) or Molar Concentration is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molatity( M)=\frac{number of moles of solute}{Volume}

Molarity is expressed in units (\frac{moles}{liter}).

In this case:

  • Molarity= 2.1 M
  • number of moles of solute= ?
  • Volume= 550 mL= 0.550 L (being 1L=1000 mL)

Replacing:

2.1 M= 2.1 \frac{moles}{liter} =\frac{number of moles of solute}{0.550 liters}

Solving:

number of moles of solute= 2.1 M* 0.550 L

number of moles of solute= 1.155 moles

1.155 moles of potassium nitrate are required to make 550 mL of a 2.1M solution.

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3 years ago
How many moles of oxygen molecule is reacting with sodium according to the following reaction:
murzikaleks [220]

<u>1 mole of oxygen.</u>

Answer:

solution given:

2Na+O_2=Na_2O_2\\2mole\:\: 1mole \:\: 1mole

according to the above reaction,1 mole of oxygen is required to react with 2 moles of sodium to form sodium peroxide.

Explanation:

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2 years ago
Emission results in the release of energy without any apparent change in mass or nuclear charge.
Sveta_85 [38]

Answer:

gamma ray

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Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

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4 years ago
The product gas is then passed through a concentrated solution of KOH to remove the CO2. After passage through the KOH solution,
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<u>Answer:</u> The mass percent of nitrogen gas in the compound is 13.3 %

<u>Explanation:</u>

Assuming the chemical equation of the compound forming product gases is:

\text{Compound}\xrightarrow[CuO(s)]{Hot}N_2(g)+CO_2(g)+H_2O(g)

Now, the product gases are treated with KOH to remove carbon dioxide.

We are given:

p_{Total}=726torr\\P_{water}=23.8torr\\

So, pressure of nitrogen gas will be = p_{Total}-p_{water}=726-23.8=702.2torr

To calculate the number of moles of nitrogen, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of nitrogen gas = 702.2 torr = 0.924 atm    (Conversion factor: 1 atm = 760 torr)

V = Volume of nitrogen gas = 31.8 mL = 0.0318 L   (Conversion factor:  1 L = 1000 mL)

T = Temperature of nitrogen gas = 25^oC=[25+273]K=298K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = ?

Putting values in above equation, we get:

0.924atm\times 0.0318L=n\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 298K\\n_{mix}=\frac{0.924\times 0.0318}{0.0821\times 298}=0.0012mol

  • To calculate the mass of nitrogen gas, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.0012 moles

Putting values in above equation, we get:

0.0012mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.0012mol\times 28g/mol)=0.0336g

  • To calculate the mass percent of nitrogen gas in compound, we use the equation:

\text{Mass percent of nitrogen gas}=\frac{\text{Mass of nitrogen gas}}{\text{Mass of compound}}\times 100

Mass of compound = 0.253 g

Mass of nitrogen gas = 0.0336 g

Putting values in above equation, we get:

\text{Mass percent of nitrogen gas}=\frac{0.0336g}{0.253g}\times 100=13.3\%

Hence, the mass percent of nitrogen gas in the compound is 13.3 %

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