Answer:
-6
Step-by-step explanation:
It would be the distributive property. :)
6.438 is the final answer
Answer:
Step-by-step explanation:
P(D/M₁) = .04 ( probability of defect from a 1 st machine )
P(D/M₂) = .06
P(D/M₃) = .01
P( M₁ )= .3 ( probability of manufacture from 1 st machine )
P(M₂) = .2
P(M₃)= .5
P( M₁/D) ( Probability of manufacture from 1 st machine , given it is defective )
= P( M₁ )xP(D/M₁) / [P( M₁ )xP(D/M₁) +P( M₂ )xP(D/M₂)+P( M₃ )xP(D/M₃)]
= .3 x .06 / .3 x .06 + .2 x .06 + .5 x .01
= .018 / .035
= 18/35
Answer: I think the answer is Infinity.
Step-by-step explanation:
