Ask question

Ask question

All categories

3 years ago

12

What are the equations for motion regarding distance, velocity, acceleration. Also, please mention that the equations would be i

f the object was in free fall

1 answer:

Ilia_Sergeevich [38]3 years ago

5 0

Answer:

$d=d_0+v_0t+\frac{at^2}{2}$ ; $v=v_0+at$

$y=y_0+v_{0y}t+\frac{gt^2}{2}$ ; $x=x_0+v_{0x}t$

$v_y=v_{0y}+gt$ ; $v_x=v_{0x}$

Explanation:

The equations of accelerated motion regarding distance, velocity, acceleration are:

$d=d_0+v_0t+\frac{at^2}{2}$

$v=v_0+at$

If the object were in free fall, these would be (taking the downward direction as positive):

$y=y_0+v_{0y}t+\frac{gt^2}{2}$

$x=x_0+v_{0x}t$

$v_y=v_{0y}+gt$

$v_x=v_{0x}$

Other equations can also be derived from the original ones, like for example $v^2=v_0^2+2a(d-d0)$

You might be interested in

what causes ocean water near the equator to be warmer than ocean water farther north? a. upwellings spew warm water toward the e

Burka [1]

The structure and curvature of the Earth results in beams of sunlight glancing off the equator and reaching other areas of the Earth. This means that the areas at the equator receive more energy as sun's rays hit them directly.
Therefore, the answer is C.

8 0

3 years ago

Read 2 more answers

A lamp is connected to the power supply.

Vika [28.1K]

Answer:

There are 45 turns in the secondary coil.

Explanation:

Given that,

Input potential of the lamp, $V_{in}=5\ V$

The output potential of the lamp, $V_{out}=1.5\ V$

Number of turns in primary coil, $N_P=150$

We need to find the number of turns needed on the secondary coil. We know that the ratio for a transformer is as follows :

$\dfrac{V_{out}}{V_{in}}=\dfrac{N_s}{N_P}\\\\N_s=\dfrac{V_{out}N_P}{V_{in}}\\\\N_s=\dfrac{1.5\times 150}{5}\\\\N_s=45\$

So, there are 45 turns in the secondary coil.

5 0

3 years ago

Aneli [31]

Always true everthing has gravity

5 0

3 years ago

Which of the following can only be a situation of increasing temperature?

Papessa [141]

Increasing the temperature causes an increase in the average kinetic energy of the particles of a material.

<h3>What is average kinetic energy of particles?</h3>

The average kinetic energy of particles is the energy possessed by particles due to their constant motion.

The constant motion of particles occurs due to the energy acquired by the particles, when the temperature of the particles increases, the average kinetic energy increases which in turn increases the speed of the particles.

Thus, we can conclude that, increasing the temperature causes an increase in the average kinetic energy of the particles of a material.

Learn more about average kinetic energy here: brainly.com/question/9078768

5 0

3 years ago

Kyle is flying a helicopter at 125 m/s on a heading of 325 o . If a wind is blowing at 25 m/s toward a direction of 240.0 o , wh

frosja888 [35]

Answer:

The resultant velocity of the helicopter is $\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)$ .

Explanation:

Physically speaking, the resulting velocity of the helicopter ( $\vec v_{H}$ ), measured in meters per second, is equal to the absolute velocity of the wind ( $\vec v_{W}$ ), measured in meters per second, plus the velocity of the helicopter relative to wind ( $\vec v_{H/W}$ ), also call velocity at still air, measured in meters per second. That is:

$\vec v_{H} = \vec v_{W}+\vec v_{H/W}$ (1)

In addition, vectors in rectangular form are defined by the following expression:

$\vec v = \|\vec v\| \cdot (\cos \alpha, \sin \alpha)$ (2)

Where:

$\|\vec v\|$ - Magnitude, measured in meters per second.

$\alpha$ - Direction angle, measured in sexagesimal degrees.

Then, (1) is expanded by applying (2):

$\vec v_{H} = \|\vec v_{W}\| \cdot (\cos \alpha_{W},\sin \alpha_{W}) +\|\vec v_{H/W}\| \cdot (\cos \alpha_{H/W},\sin \alpha_{H/W})$ (3)

$\vec v_{H} = \left(\|\vec v_{W}\|\cdot \cos \alpha_{W}+\|\vec v_{H/W}\|\cdot \cos \alpha_{H/W}, \|\vec v_{W}\|\cdot \sin \alpha_{W}+\|\vec v_{H/W}\|\cdot \sin \alpha_{H/W} \right)$

If we know that $\|\vec v_{W}\| = 25\,\frac{m}{s}$ , $\|\vec v_{H/W}\| = 125\,\frac{m}{s}$ , $\alpha_{W} = 240^{\circ}$ and $\alpha_{H/W} = 325^{\circ}$ , then the resulting velocity of the helicopter is:

$\vec v_{H} = \left(\left(25\,\frac{m}{s} \right)\cdot \cos 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \cos 325^{\circ}, \left(25\,\frac{m}{s} \right)\cdot \sin 240^{\circ}+\left(125\,\frac{m}{s} \right)\cdot \sin 325^{\circ}\right)$ $\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)$

The resultant velocity of the helicopter is $\vec v_{H} = \left(89.894\,\frac{m}{s}, -93.348\,\frac{m}{s}\right)$ .

8 0

3 years ago