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A 5kg cart moving to the right with a velocity of 16 m/s collides with a concrete wall and

Kryger [21]

Explanation:

mass, m = 5kg

initial velocity, u = 16m/s

final velocuty, v = -22m/s

change in momentum, ∆p = ?

∆p = m (v-u)

5(-22-16)

5(38)

∆p = 190kgm/s

check the calculations!

8 0

2 years ago

How many star are thier in the universe

FrozenT [24]

<h2>About 1 trillion billion stars (21 0's)</h2><h2 />

There is an average of 100 billion stars per galaxy. But you are looking for a universe, which is bigger than a galaxy.

According to UCSB Science Line, there are about 1 trillion billion stars in the observable universe. That's one 1 and twenty-one 0's.

3 0

3 years ago

A 0.10-kilogram piece of modeling clay is tossed

viva [34]

a) The initial speed of the clay is 30 m/s

b) The final velocity of the block increases (40 m/s)

Explanation:

a)

We can solve this problem by using the law of conservation of momentum. In fact, in absence of external forces (=no friction), the total momentum of the clay + block system is conserved before and after the collision. Therefore, we can write:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 0.10 kg$ is the mass of the clay

$u_1$ is the initial velocity of the clay

$m_2 = 0.10 kg$ is the mass of the wood block

$u_2 = 0$ is the initial velocity of the wood block (at rest)

$v = 15 m/s$ is the final combined velocity of the clay+block after the collision

Re-arranging the equation, we can find $u_1$ , the speed at which the clay was tossed:

$u_1 = \frac{(m_1+m_2)v-m_2 u_2}{m_1}=\frac{(0.10+0.10)(15)-0}{0.10}=30 m/s$

b)

In this second case, the clay is replaced by a bouncy ball, which rebounds back after the collision, instead of sticking with the block.

In this second case, the law of conservation of momentum becomes:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2$

where

$m_1 = 0.10 kg$ is the mass of the ball

$u_1 = 30 m/s$ is the initial velocity of the ball

$m_2 = 0.10 kg$ is the mass of the wood block

$u_2 = 0$ is the initial velocity of the wood block (at rest)

$v_1 = -10 m/s$ is the velocity of the bouncing ball after the collision (negative because it goes backward)

$v_2$ is the velocity of the block after the collision

Solving for $v_2$ , we find the final velocity of the block:

$v_2 = \frac{m_1 u_1 - m_1 v_1}{m_2}=\frac{(0.10)(30)-(0.10)(-10)}{0.10}=40 m/s$

As we can see, the final velocity of the block has increased. The reason for that is that, as the ball bounces back, part of the total momentum is "carried away" by the ball in the backward direction, and since the total momentum must remain constant, this means that the momentum carried by the block in the forward direction must be larger than the previous situation.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

7 0

3 years ago

5.

SVETLANKA909090 [29]

Answer: black

Explanation: When green light is shone on a red object, it absorbs all of the green light and not reflecting anything. Hence, it appears black.

8 0

3 years ago

Are the days with the longest daylight always in the summer? Are the days with the shortest daylight always in the winter? Expla

jok3333 [9.3K]

The day with the longest daylight is the beginning of Summer.
After that, they start to get shorter.

The day with the shortest daylight is the beginning of Winter.
After that, they start to get longer.

6 0

3 years ago