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3 years ago

Help ASAP!

Physics

1 answer:

Aneli [31]3 years ago

5 0

Always true everthing has gravity

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If Ike notices that there is a new moon tonight, when should he expect there to be a new moon again?

podryga [215]

Whatever phase of the moon Ike sees, he can expect to see
the same phase of moon again, after 29.53 days later.

5 0

3 years ago

Three equal 1.55-μC point charges are placed at the corners of an equilateral triangle whose sides are 0.500 m long. What is the

kati45 [8]

Answer:

0.12959085 J

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = 1.55 μC

d = Distance between charge = 0.5 m

Electric potential energy is given by

$U=k\dfrac{q^2}{d}$

In this system with three charges which are equidistant from each other

$U=k\dfrac{q^2}{d}+k\dfrac{q^2}{d}+k\dfrac{q^2}{d}$

$\\\Rightarrow U=k\dfrac{3q^2}{d}\\\Rightarrow U=8.99\times 10^9\times \dfrac{3\times (1.55\times 10^{-6})^2}{0.5}\\\Rightarrow U=0.12959085\ J$

The potential energy of the system is 0.12959085 J

6 0

3 years ago

Determine the diameter of the largest circular hole that can be punched into a sheet of polystyrene 6 mm thick, knowing that the

Yakvenalex [24]

Answer:

43.41 mm

Explanation:

Given:

thickness of sheet, t = 6 mm

Force exerted by punch, F = 45 KN

Average shearing stress, T = 55 MPa

From average shearing stress T = Force F / Area A

Hence area = force/stress =45000/ 55 = $818.18 mm^2$

From area = pi*diameter*thickness

diameter = area/(pi* thickness)

= 818.18/(3.142*6)

= 43.41 mm

4 0

3 years ago

Help on this pls. !!!!!

Luba_88 [7]

Answer:

Explanation:

4 0

3 years ago

Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road oriented at an angle of 25

rjkz [21]

Answer:

8.6 miles

Explanation:

In order to calculate the straight-line distance between the starting point and the ending point, we need to resolve each part of the displacement into two perpendicular directions, let's say horizontal (x) and vertical (y) directions.

In the first part, Erica moves for 5.2 miles 25∘ north of east. Resolving into the two directions:

$d_{1x} = 5.2 cos 25^{\circ}=4.7 mi\\d_{1y} = 5.2 sin 25^{\circ} =2.2 mi$

In the second part, Erica moves 5.0 miles north, so the components are

$d_{2x} = 0\\d_{2y} = 5.0 mi$

So the components of the net displacement are

$d_x = d_{1x}+d_{2x}=4.7+0 = 4.7 mi\\d_y = d_{1y}+d_{2y} =2.2+5.0 = 7.2 mi$

And the magnitude of the net displacement is

$d=\sqrt{d_x^2 +d_y^2}=\sqrt{4.7^2+7.2^2}=8.6 mi$

8 0

3 years ago