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3 years ago

Which is the coolest -5°C -2°C -8°C -12°C

Mathematics

1 answer:

Virty [35]3 years ago

8 0

-12 Celsius because that would equal 10.4 degrees

You might be interested in

.. Discuss the nature of the root of equation x2 + 2x + 3 = 0

Mariana [72]

Answer:

No real roots

Step-by-step explanation:

Given equation:

x² + 2x + 3 = 0

On comparing the equation by ax² + bx + x = 0, We get: a = 1, b = 2 and c = 3

To Find the nature of the roots of the equation firstly we need to find the discriminant of the equation. The expression b²- 4ac is called the discriminant.

$~$

Two Distinct real roots, if b² - 4ac > 0
Two equal real roots, if b² - 4ac = 0
No real roots, if b² - 4ac < 0

$\\ \: \: \dashrightarrow \: \: \: \sf {b}^{2} - 4ac = 0 \\ \\ \\\: \: \dashrightarrow \: \: \: \sf (2)² - 4 \times 1 \times 3 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf 4 - 4 \times 1 \times 3 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf 4 - 12 = 0 \\ \\ \\ \: \: \dashrightarrow \: \: \: \sf {\underline{\boxed{\sf{\purple{ -8 > 0}}}}} \\ \\$

The discriminant is smaller than 0.

Hence, Equation has no real roots (no solution)

6 0

1 year ago

Solve for points. identify the vertex and indicate whether it is max or min.

Keith_Richards [23]

Answer:

min at (3, 0 )

Step-by-step explanation:

given a quadratic in standard form

y = ax² + bx + c ( a ≠ 0 )

then the x- coordinate of the vertex is

$x_{vertex}$ = - $\frac{b}{2a}$

y = (x - 3)² = x² - 6x + 9 ← in standard form

with a = 1 and b = - 6 , then

$x_{vertex}$ = - $\frac{-6}{2}$ = 3

substitute x = 3 into the equation for corresponding value of y

y = (3 - 3)² = 0² = 0

vertex = (3, 0 )

• if a > 0 then vertex is minimum

• if a < 0 then vertex is maximum

here a = 1 > 0 then (3, 0 ) is a minimum

4 0

1 year ago

In a certain residential suburb, 60% of all households get Internet service from the local cable company, 80% get television ser

Serggg [28]

Answer:

a) 0.900

b) 0.400

Step-by-step explanation:

Let I = households getting internet

T = households getting television

Then I = 60%

and T = 80%

$I\cap T = 50\%$ (Households that get both services)

a) Households getting at least one service, $I\cup T = I + T - I\cap T= 60+80-50 =90\%=0.900$

b) Those getting internet only = $I - I\cap T = 60 - 50 = 10\% = 0.1$

Those getting television only = $T - I\cap T = 80- 50=30\%=0.3$

Probability of getting exactly one service = 0.1 + 0.3 = 0.400

6 0

3 years ago

Question 6

77julia77 [94]

Answer:

9.28/2.9=3.2is a required answer

4 0

2 years ago

Read 2 more answers

HELP ASAP

Andrei [34K]

Answer:

$radius = \sqrt{13}$ or $radius = 3.61$

Step-by-step explanation:

Given

Points:

A(-3,2) and B(-2,3)

Required

Determine the radius of the circle

First, we have to determine the center of the circle;

Since the circle has its center on the x axis; the coordinates of the center is;

$Center = (x,0)$

Next is to determine the value of x through the formula of radius;

$radius = \sqrt{(x_1 - x)^2 + (y_1 - y)^2} = \sqrt{(x_2 - x)^2 + (y_2 - y)^2}$

Considering the given points

$A(x_1,y_1) = A(-3,2)$

$B(x_2,y_2) = B(-2,3)$

$Center(x,y) =Center (x,0)$

Substitute values for $x,y,x_1,y_1,x_2,y_2$ in the above formula

We have:

$\sqrt{(-3 - x)^2 + (2 - 0)^2} = \sqrt{(-2 - x)^2 + (3 - 0)^2}$

Evaluate the brackets

$\sqrt{(-(3 + x))^2 + 2^2} = \sqrt{(-(2 + x))^2 + 3 ^2}$

$\sqrt{(-(3 + x))^2 + 4} = \sqrt{(-(2 + x))^2 + 9}$

Eva;uate all squares

$\sqrt{(-(3 + x))(-(3 + x)) + 4} = \sqrt{(-(2 + x))(-(2 + x)) + 9}$

$\sqrt{(3 + x)(3 + x) + 4} = \sqrt{(2 + x)(2 + x) + 9}$

Take square of both sides

$(3 + x)(3 + x) + 4 = (2 + x)(2 + x) + 9$

Evaluate the brackets

$3(3 + x) +x(3 + x) + 4 = 2(2 + x) +x(2 + x) + 9$

$9 + 3x +3x + x^2 + 4 = 4 + 2x +2x + x^2 + 9$

$9 + 6x + x^2 + 4 = 4 + 4x + x^2 + 9$

Collect Like Terms

$6x -4x + x^2 -x^2 = 4 -4 + 9 - 9$

$2x = 0$

Divide both sides by 2

$x = 0$

This implies the the center of the circle is

$Center = (x,0)$

Substitute 0 for x

$Center = (0,0)$

Substitute 0 for x and y in any of the radius formula

$radius = \sqrt{(x_1 - 0)^2 + (y_1 - 0)^2}$

$radius = \sqrt{(x_1)^2 + (y_1)^2}$

Considering that we used x1 and y1;

In this case we have that; $A(x_1,y_1) = A(-3,2)$

Substitute -3 for x1 and 2 for y1

$radius = \sqrt{(-3)^2 + (2)^2}$

$radius = \sqrt{13}$

$radius = 3.61$ ---Approximated

7 0

3 years ago