The inclination to the nearest tenth of a degree exists 0.24146
<h3>What is the inclination to the nearest tenth of a degree?</h3>
The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.
Given: H = 4.6 m and P = 1.1 m
We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse
Let x be the angle then
sin x = P/H
sin x = 1.1/4.6
sin x = 0.23913
= 0.24146
The inclination to the nearest tenth of a degree exists 0.24146
To learn more about trigonometric ratios refer to:
brainly.com/question/14033725
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Answer:
k = -9
Step-by-step explanation:
subtract 2k from both sides
_5k+8= -37
subtract 8
_5k = -45
divide by 5
_k = -9
Answer:
56.25 pi cm^2
Step-by-step explanation:
To find the area of the circle,
we use the formula
A = pi r^2, where r is the radius
We know the diameter is 15 so we can find the radius from
r = d/2 where d is the diameter
r = 15/2
A = pi ( 15/2) ^2
A = pi ( 225/4)
A = 56.25 pi cm^2
The equations give you information as to where to plot points.
For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.
For y = -2x + 4, the slope is -2 (so it will also slope downwards), and the y-intercept is 4. Find (0, 4) and plot it. The -2 tells you to count 2 units down (instead of 1 like we did for the last equation) and 1 over. That is the second line.
I hope this helps.
