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slamgirl [31]
4 years ago
14

Is distance and displacement the same thing

Physics
1 answer:
Elden [556K]4 years ago
4 0

Both Distance and displacement deals the distance of the object but they differ distinct is scalr quantity and displacement is vector quantity or have Direction

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As a box is pushed 30 meters across a horizontal floor by a constant horizontal force of 25 newtons, the kinetic energy of the b
irakobra [83]

Answer:

1,050 Joules

Explanation:

<u>Step 1:</u> work done in moving the box 30 meters

work done = force X distance

                  = 25N X 30 = 750 Joules

<u>Step 2: </u>calculate total internal energy

Total internal energy = work done + kinetic energy

                                   = 750 Joules + 300 Joules

                                   = 1,050 Joules = 1.05 KJ

5 0
3 years ago
What was David Berkowitz best known for? How did arson play a role in his past?
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5 0
3 years ago
Read 2 more answers
at a certain moment, an object has an amount of 200 of motion energy and 400 of gravitational potential energyThe object is also
Radda [10]

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twice as much energy

Explanation:

8 0
2 years ago
Friction is a force in which two objects __________.
balu736 [363]
The answer should be C) Slide against each other.
7 0
3 years ago
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Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr
Stolb23 [73]

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

weight of water = 1 * 11.2^2 * x

we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

6 0
3 years ago
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