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kondor19780726 [428]
3 years ago
12

Un cubo de madera de densidad 0.780 g/cm³ mide 11.2 cm en un lado. Cuando se coloca en agua, ¿qué altura del bloque flotará sobr

e la superficie? (densidad de agua a 1.00 g/cm³)
Physics
1 answer:
Stolb23 [73]3 years ago
6 0

Answer:

2.464 cm above the water surface

Explanation:

Recall that for the cube to float, means that the volume of water displaced weights the same as the weight of the block.

We calculate the weight of the block multiplying its density (0.78 gr/cm^3) times its volume (11.2^3  cm^3):

weight of the block = 0.78 * 11.2^3  gr

Now the displaced water will have a volume equal to the base of the cube (11.2 cm^2) times the part of the cube (x) that is under water. Recall as well that the density of water is 1 gr/cm^3.

So the weight of the volume of water displaced is:

weight of water = 1 * 11.2^2 * x

we make both weight expressions equal each other for the floating requirement:

0.78 * 11.2^3 = 11.2^2 * x

then x = 0.78 * 11.2 cm = 8.736 cm

This "x" is the portion of the cube under water. Then to estimate what is left of the cube above water, we subtract it from the cube's height (11.2 cm) as follows:

11.2 cm - 8.736 cm = 2.464 cm

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Answer:

F = 8 N

Explanation:

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Given that,

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We need to find the magnitude of this force. We know that, the torque acting on an object is given by :

\tau=Fd\\\\F=\dfrac{\tau}{d}\\\\F=\dfrac{0.4\ N-m}{0.05\ m}\\\\F=8\ N

So, the magnitude of force is equal to 8 N.

8 0
3 years ago
Light of wavelength 500nm shines on a pair of slits. This produces an interference pattern on a screen 2.00m behind the slits. M
grandymaker [24]

Answer:

The  value is  d = 0.000125 \  m

Explanation:

From the question we are told that

   The  wavelength is  \lambda  =  500 \  nm =  500 *10^{-9 } \  m

    The  distance is of  the screen is  D =  2.0 \ m

    The  width of the fifth dark spot is y  =  4.00 \  cm  =  0.04 \  m

Generally the width of a fringe is mathematically represented as

           y =  \frac{ n  *  \lambda  *  D }{d }

=>        0.04  =  \frac{ 5  * 500 *10^{-9}  *  2 }{d}

=>        d =  \frac{ 5  * 500 *10^{-9}  *  2 }{0.04}

=>        d = 0.000125 \  m

7 0
3 years ago
Suppose an elephant has a mass of 2850 kg. show answer No Attempt How fast, in meters per second, does the elephant need to move
Bad White [126]

Answer:

1.23 m/s

Explanation:

The kinetic energy of the sprinter is:

KE = 0.5 * m(s) * v²

KE = 0.5 * 77 * 7.5²

KE = 2165.63 J

If the KE of the sprinter and the KE of the elephant are equal, hence:

2165.63 = 0.5 * m(e) * v²

2165.63 = 0.5 * 2850 * v²

=> v² = 1.52

v = √(1.52)

v = 1.23 m/s

6 0
3 years ago
A 0.40-kg mass attached to the end of a string swings in a vertical circle having a radius of 1.8 m. At an instant when the stri
enyata [817]

Answer:

T=8.1N

Explanation:

From the question we are told that:

Mass m=0.40

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Angle Beneath the Horizontal \theta =40 \textdegree

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The Tension Angle

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Generally the equation for Tension is is mathematically given by

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Varvara68 [4.7K]

Answer:

55 mA

Explanation:

Ohm's law states:

V = IR

where V is voltage, I is current, and R is resistance.

220 V = I (4000 Ω)

I = 0.055 A

I = 55 mA

7 0
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