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jek_recluse [69]
3 years ago
12

How does the range of the pumpkin change if its initial velocity is tripled (keeping the angle fixed and less than 90∘)? How doe

s the range of the pumpkin change if its initial velocity is tripled (keeping the angle fixed and less than )? The pumpkin's range is nine times as far. The pumpkin's range is eighteen times as far. The pumpkin's range is three times as far.
Physics
1 answer:
Deffense [45]3 years ago
5 0

Answer:

The pumpkin's range is nine times as far.

Explanation:

Given,

In the first case,

Let a pumpkin is thrown with initial velocity u with an angel theta above the horizontal axis.

Therefore the range of the pumpkin is,

R\ =\ \dfrac{u^2sin2\theta}{g}\,\,\,\,\,\,\,\,\,\,\,\,eqn(1)

Now in the second case

Initial velocity of the pumpkin is three times the first case,

\therefore U\ =\ 3u

Let R' be the new range of the pumpkin.

New range of the pumpkin is,

\therefore R'\ =\ \dfrac{U^2sin2\theta}{g}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,eqn(2)

From eqn (1) and (2), we get,

\therefore R'\ =\ \dfrac{(3u)^2sin2\theta}{g}\\\Rightarrow R'\ =\ \dfrac{9u^2sin2\theta}{g}\\\Rightarrow R'\ =\ 9 R

Hence the pumpkin's range is nine times of the initial case.

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A 55 kg track and field athlete has an average power output of 5.4 kW during the 200 meter dash. How quickly did she finish the
olga_2 [115]

The time taken for the athlete to finish the race is 20 s (Option A)

<h3>What is power? </h3>

Power is simply defined as the rate at which work is done. It can be expressed mathematically as

Power (P) = work (W) / time (t)

But

Work = weight × distance

Therefore,

Power = (weight × distance ) / time

<h3>How to determine the time </h3>
  • Mass (m) = 55 Kg
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Power = (weight × distance ) / time

5400 = (539 × 200) / t

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Cross multiply

5400 × t = 107800

Divide both side by 5400

t = 107800 / 5400

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5 0
1 year ago
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
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Answer:Highest frequency  =618.89Hz

Lowest frequency=582.22Hz

Explanation:

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Vs = rω  where

r = the radius of circular path = 1.0 m

ω is the angular velocity of the sound generator. = 100 rpm

1 rev/min = 0.10472 rad/s

100rpm =10.472 rad/ s

Vs = rω

= 1m x 10.472rad/ s=  10.472m/s

A) Highest frequency  heard by a student in the classroom = Maximum frequency. Using the Doppler effect formulae,

f max = (v/ v-vs) fs

Where , v is the speed of the sound in air at 20 degrees celcius =

343 metres per second

vs is the linear velocity of the sound generator=10.472m/s

fs is the frequency of the sound generator= 600 Hz

f max = (343/ 343 - 10.472) x 600

=343/332.528) x600

=618.89Hz

B) Lowest frequency  heard by a student in the classroom = Minimum frequency

f min = (v/ v+vs) fs

(343/ 343 + 10.472) x 600

=343/353.472) x 600

=582.22hz

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3 years ago
What is the eccentricity of an ellipse with a foci distance of 50,000,000 km and
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25,000,000 Km ;)

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