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svp [43]
3 years ago
14

As a box is pushed 30 meters across a horizontal floor by a constant horizontal force of 25 newtons, the kinetic energy of the b

ox increases by 300 joules.
How much total internal energy is produced during this process?
Physics
1 answer:
irakobra [83]3 years ago
5 0

Answer:

1,050 Joules

Explanation:

<u>Step 1:</u> work done in moving the box 30 meters

work done = force X distance

                  = 25N X 30 = 750 Joules

<u>Step 2: </u>calculate total internal energy

Total internal energy = work done + kinetic energy

                                   = 750 Joules + 300 Joules

                                   = 1,050 Joules = 1.05 KJ

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Explanation:

1) Notation and info given

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So then our linear model would be

\rho (r)=\rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r

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M=\int \rho (r) dV

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M=\int_{0}^{2\pi}d\phi \int_{0}^{\pi}sin\theta d\theta \int_{0}^{r_{earth}}(r^2 \rho_{center}+\frac{\rho_{surface}-\rho_{center}}{r_{earth}}r)

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M=4\pi(\frac{r^3_{earth}\rho_{center}}{3}+\frac{r^4_{earth}}{4} \frac{\rho_{surface}-\rho_{center}}{r_{earth}})

Simplyfind this last expression we have:

M=\frac{4\pi\rho_{center}r^3_{earth}}{3}+\pi r^3_{earth}(\rho_{surface}-\rho_{center})

M=\pi r^3_{earth}(\frac{4}{3}\rho_{center}+\rho_{surface}-\rho_{center})

M=\pi r^3_{earth}[\rho_{surface}+\frac{1}{3}\rho_{center}]

And replacing the values we got:

M=\pi (6.371x10^{6}m)^2(\frac{1}{3}13000 \frac{kg}{m^3}+2100 \frac{kg}{m^3})=8.204x10^{24}kg

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