Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?

1 answer:

4 0

Hello there i hope you are having a good day :) Question : Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?

So Firstly when lifting a box you would need to be vertically and you would need to added to calculate the total forces that its gravitational force, tension force and also air resistance force.

Hopefully this helps you.

You might be interested in

The phosphorus cycle is the biogeochemical cycle that describes the movement of phosphorus through the lithosphere,

ludmilkaskok [199]

most common source of phosphates in the soil is the weathering of the mineral apatite.

Explanation:

Apatite is a group of phosphate minerals like hydroxylapatite, fluorapatite, and chlorapatite. When apatite rocks weather, they release the phosphate minerals mainly in the form of PO₄ ³⁻ . These minerals become dissolved in water (hydrosphere), where they are readily available to plants and other organisms in the biosphere. The phosphates are taken up and used in biosynthesis. When these organisms die and become buried with sediments, the phosphate gets back to the lithosphere as sedimentary rock.

Learn More:

For more on phosphorus cycle check out;

brainly.com/question/1796604

brainly.com/question/4160476

#LearnWithBrainly

5 0

2 years ago

List the planet name and position from the Sun for each one (1, 2, 3)

IgorLugansk [536]

Answer:

The planets in order from the sun are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, Neptune and finally the dwarf planet Pluto. Most people have at least heard about our solar system and the planets in it.

Explanation:

<h3><u><em>please mark me brainliest</em></u></h3>

8 0

1 year ago

Incident rays parallel to the principle axis of a concave mirror will reflect _____. parallel to the principle axis through the

Svetradugi [14.3K]

I’m not sure if its correct but I think it’s focal Ray point

For concave mirrors, some generalizations can be made to simplify ray construction. They are: An incident ray traveling parallel to the principal axis will reflect and pass through the focal point. An incident ray traveling through the focal point will reflect and travel parallel to the principal axis.

8 0

3 years ago

Read 2 more answers

a large sphere is on a horizontal field on a sunny day. at a certain time the shadow reaches out a distance of 10 m from the poi

Mars2501 [29]

The radius of the sphere in meters is ,r = $10\sqrt{5} -20$

Think about the angle the ground and the shadow make. Since the sun's beams are parallel, the angle created by the stick's shadow is also equal. Since the stick is 1 m high and its shadow is 2 m long, we know that the stick's angle is arctan 1/2. Therefore, by thinking of a right-angled triangle,

r/10 = tan [arctan(1/2)] = tan (1/2)

Since, tan (θ/2) = 1-cos(θ) / sin(θ)

we find that,

r/10 = $\sqrt{5} -2$