The magnitude of the vector C is 96.32m
<h3>How to solve for the magnitude of vector c</h3>
Ax = AcosθA
= 40 cOS 20
= 37.59
Ay = AsinθA
-40sin20
= -13.68
Bx = B cos θ B
= 75Cos50
= 48.21
By = BsinθB
= 75sin50
= 57.45
Cx = AX + Bx
= 37.59 + 48.21
= 85.8
Cy = Ay + By
= -13.65 + 57.45
= 43.77
The magnitude is solved by
|c| =
= √85.8² + 43.77²
= 96.32m
The magnitude of the vector c is 96.32m
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Answer:
150 km/hr²
Explanation:
The data for the motion of the train includes;
The train starts from rest, therefore, the initial velocity of the train, u = 0 km/hr
The speed of the train after 0.5 hours, v = 75 km/hr
The change in time during the motion of the train, Δt = 0.5 hours
The acceleration, 'a', is the rate of change of velocity with time;
Therefore, we have;
a = (75 km/hr - 0 km/hr)/(0.5 hr) = 150 km/hr²
a = 150 km/hr² = 150 km/hr² × 1,000 m/km × hr²/(3,600 s)² = 5/432 m/s²
The acceleration of the train, a = 150 km/hr² = 5/432 m/s².