All categories

3 years ago

Is frequent anger a problem for you? If so, what strategies could you try to overcome it?

Physics

1 answer:

erastova [34]3 years ago

3 0

Answer:

I tend to slap thicc trees a#ss

Explanation:

You might be interested in

If the velocity versus time graph of an object is a horizontal line, the object is

FromTheMoon [43]

A. Moving with constant non-zero speed

3 0

2 years ago

Read 2 more answers

gregori [183]

Answer:

1. Revolve around a point

2. Formed from dust and gas particles

3. Exoplanets and associated star orbit a common center of mass

4. Composed of gases found in Jupiter and Saturn

3 0

2 years ago

If the speed of a car is 20m/s .How long does it take to cover a distance of 1km?<br>

3241004551 [841]

Answer: 50 seconds

Explanation:

1km=1000m

Distance/speed=time

1000/20=50

50 seconds

7 0

2 years ago

Read 2 more answers

astronauts in space cannot weigh themselves by standing on a bathroom scale. Instead, they determine their mass by oscillating o

devlian [24]

Answer:

The right answer is:

(a) 63.83 kg

(b) 0.725 m/s

Explanation:

The given query seems to be incomplete. Below is the attachment of the full question is attached.

The given values are:

T = 3 sec

k = 280 N/m

(a)

The mass of the string will be:

⇒ $T=2 \pi\sqrt{\frac{m}{k} }$

or,

⇒ $m=\frac{k T^2}{4 \pi^2}$

On substituting the values, we get

⇒ $=\frac{280\times (3)^2}{4 \pi^2}$

⇒ $=\frac{280\times 9}{4\times (3.14)^2}$

⇒ $=68.83 \ kg$

(b)

The speed of the string will be:

⇒ $\frac{1}{2}k(0.4)^2=\frac{1}{2}k(0.2)^2+\frac{1}{2}mv^2$

then,

⇒ $v=\sqrt{\frac{k((0.4)^2-(0.2)^2)}{m} }$

On substituting the values, we get

⇒ $=\sqrt{\frac{280\times ((0.4)^2-(0.2)^2)}{63.83} }$

⇒ $=\sqrt{\frac{280(0.16-0.04)}{63.83} }$

⇒ $=\sqrt{\frac{280\times 0.12}{63.83} }$

⇒ $=0.725 \ m/s$

4 0

3 years ago

Light will not pass through a pair of polaroids when their axes are

Advocard [28]

Answer:

perpendicular

Explanation:

Polaroids are the material that is used to polarize the ray of light. Polaroid consists of microcrystals of herapathite.

When unpolarized light is passed through the Polaroid then ray appears to be of half the intensity and vibration of the ray in the single plane so, the emerged light is known as polarized light

Polaroids are used in the glasses to protect the eye from unwanted rays.

When Light does not pass through a pair of Polaroids then the axis of Polaroids will be perpendicular to the axis of ray.

8 0

2 years ago