Folds and faults are difficult to identify because they occur in the interior of rocks and also due to the dense nature of the materials.
<h3>What are faults and folds?</h3>
Faults are lines of weakness are present in materials dues to uneven positioning of the particles of the material.
Folds occurs when infolds occur in materials.
Faults and folds usually occur in rocks.
Folds and faults are difficult to identify because they occur internally and also due to the dense nature of the materials.
Learn more about faults and folds at: brainly.com/question/14240712
Two types of mechanical waves: longitudinal<span> waves and </span>transverse<span> waves; the medium movement differs between the two.
</span>In a longitudinal wave the medium particle movement is parallel to the direction of wave propagation; example is sound wave in air.
I<span>n a transverse wave the medium particle movement is perpendicular to the direction of wave propagation; example is mechanical wave on a string.
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Answer:
The distance traveled during its acceleration, d = 214.38 m
Explanation:
Given,
The object's acceleration, a = -6.8 m/s²
The initial speed of the object, u = 54 m/s
The final speed of the object, v = 0
The acceleration of the object is given by the formula,
a = (v - u) / t m/s²
∴ t = (v - u) / a
= (0 - 54) / (-6.8)
= 7.94 s
The average velocity of the object,
V = (54 + 0)/2
= 27 m/s
The displacement of the object,
d = V x t meter
= 27 x 7.94
= 214.38 m
Hence, the distance the object traveled during that acceleration is, a = 214.38 m
If you know an element’s atomic number, you will learn the number of protons and electrons. The atomic number is equal to the number or protons and electrons. You can also find the number of neutrons, by subtracting the atomic mass from the atomic number.
For example, Fluorine’s atomic number is 9, and its atomic mass is 19. So, the number of electrons and protons in fluorine is 9. The number of neutrons the is equal to 19-9. Thus, Fluorine has 10 neutrons.
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Answer: 87500J
Explanation:
Given that,
Power exerted by crane = 3,500 W
Time taken = 25 seconds
work done by crane = ?
Since power is the rate of work done per unit time, then power is workdone by the crane divided by the time taken.
i.e power = work / time
3,500 W = work / 25 seconds
Work = 3500W x 25 seconds
Work = 87500J
Thus, 87500 joules of work was done by the crane.