A group of 10 students participate in chess club, karate club, or neither. Let event A = The student is in karate club. Let even
t B = The student is in chess club.
One of these students is randomly selected. What is P(A/B)?
One of these students is randomly selected. What is P(A/B)?
1 answer:
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The answer is 
.
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is
, 3 can be multiplied by 2 to get 6, which is the other fraction, we can multiply it. Whatever you do to the denominator you must do to the numerator. Now multiply 2 by the numerator (10) to get 
. Now we can subtract the fractions and 
to get 13/6. Since this fraction is not in mixed fraction form yet, we must do that first. goes into 13 twice, so the whole number is 2 and there is still 1 left, making the fraction 
. Therefore, the difference is 2 .
Explanation:
In order to subtract the fractions, we must make them like fractions. To do this, the denominators must be the same by multiplying (only). Since the first fraction is