The statement 'energy cannot be created or destroyed' BEST supports the idea that energy remains constant during an energy transformation. It is the first law of thermodynamics.
<h3>Law of Conservation of Energy</h3>
The law of conservation of energy, also known as the first law of thermodynamics, indicates that energy can neither be created nor destroyed.
According to this law, the energy can be interchanged from one type of energy (e.g., kinetic energy) form to another (e.g., potential energy).
The first law of thermodynamics is fundamental for understanding major science disciplines, and it is a rosetta stone in physics.
Learn more about the first law of thermodynamics here:
brainly.com/question/7107028
Using the law of conservation of angular momentum, we have
<span>I1 w1 = I2 w2 </span>
<span>ie., m1r^2/2 x w1 = ( m1r^2/2 + m2r^2 ) w2 </span>
<span>ie., new angular velocity w2 = m1 w1 / ( m1+ 2m2) = 125 x 3.1 / ( 125 + 2 x39.5 ) </span>
<span>= 1.8995 = 1.9 rad /sec ( nearly )</span>
Answer:
Explanation:
mass of baseball, m = 0.145 kg
initial velocity, u = 12 m/s upward
(a) final velocity, v = u / 2 = 6 m/s
Let the height is h.
Use third equation of motion
v² = u² - 2gh
6 x 6 = 12 x 12 - 2 x 9.8 x h
36 - 144 = - 19.6 x h
h = 5.51 m
(b) initial kinetic energy, K = 0.5 x m x u² = 0.5 x 0.145 x 12 x 12 = 10.44 J
Final kinetic energy, K' = K/2
0.5 x m x v² = 10.44 /2
0.5 x 0.145 x v² = 5.22
v = 8.5 m/s
v² = u² - 2gh
8.5 x 8.5 = 12 x 12 - 2 x 9.8 x h
72.25 - 144 = - 19.6 x h
h = 3.66 m
Answer:
F= 4788 N
Explanation:
Because the car moves with uniformly accelerated movement we apply the following formula:
vf²=v₀²+2*a*d Formula (1)
Where:
d:displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Data
d=36.9 m
v₀=14.0 m/s m/s
vf= 0
Calculating of the acceleration of the car
We replace dta in the formula (1)
vf²=v₀²+2*a*d
(0)²=(14)²+2*a*(36.9)
-(14)²= (73.8) *a
a= - (196) / (73.8)
a= - 2.66 m/s²
Newton's second law of the car in direction horizontal (x):
∑Fx = m*ax Formula (2)
∑F : algebraic sum of the forces in direction x-axis (N)
m : mass (kg)
a : acceleration (m/s²)
Data
m=1800 Fkg
a= - 2.66 m/s²
Magnitude of the horizontal net force (F) that is required to bring the car to a halt in a distance of 36.9 m :
We replace data in the formula (2)
-F= (1800 kg) * ( -2.66 m/s²
)
F= 4788 N
The answer would be 0.40m. you are finding how far the distance is between 10 and 50
