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wel
2 years ago
10

Please help!!~

Physics
1 answer:
lisov135 [29]2 years ago
7 0

Answer:

C. Waves transfer energy, but not matter.

Explanation: hope this helps :)

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Lowest frequency of wave
Harlamova29_29 [7]
The answer would be a radio wave
4 0
3 years ago
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Two point charges, a +45nC charge X and a +12nC charge Y are separated by a distance of 0.5m.
Gnoma [55]

A) Calculate the resultant electric field strength at the midpoint between the charges.

Qx is the charge at X and Qy is the charge at Y.

E at midpoint = k×Qx/0.25² - k×Qy/0.25²

k = 9×10⁹Nm²C⁻², Qx = 45nC, Qy = 12nC

E = 4752N/C

Well done.

B) Calculate the distance from X at which the electric field strength is zero.

Let D be some point between X and Y for which the net E field is 0.

Let d be the distance from X to D.

Set up the following equation:

E at D = k×Qx/d² - k×Qy/(0.5-d)² = 0

Do some algebra to solve for d:

k×Qx/d² = k×Qy/(0.5-d)²

Qx/d² = Qy/(0.5-d)²

Qx(0.5-d)² = Qyd²

(0.5-d)√Qx = d√Qy

0.5√Qx-d√Qx = d√Qy

d(√Qx+√Qy) = 0.5√Qx

d = (0.5√Qx)/(√Qx+√Qy)

Plug in Qx = 45nC, Qy = 12nC

d ≈ 330mm

C) Calculate the magnitude of the electric field strength at the point P on the diagram below.

First determine the angles of the triangle. The sides of the triangle are 0.3m, 0.4m, and 0.5m, so this is a right triangle where the angle between the 0.3m and 0.4m sides is 90°

∠Y = tan⁻¹(0.4/0.3) = 53.13°

∠X = 90-∠Y = 36.87°

Determine the horizontal component of E at P:

Ex = E from Qx × cos(∠X) - E from Qy × cos(∠Y)

Ex = k×Qx/0.4²×cos(36.87°) - k×Qy/0.3²×cos(53.13°)

Ex = 1305N/C

Determine the vertical component of E at P:

Ey = E from Qx × sin(∠X) - E from Qy × sin(∠Y)

Ey = k×Qx/0.4²×sin(36.87°) - k×Qy/0.3²×sin(53.13°)

Ey = 2479N/C

Use the Pythagorean theorem to determine the magnitude of E at P:

E = √(Ex²+Ey²)

E ≈ 2802N/C

4 0
3 years ago
An unknown substance has a mass of 15 g and a volume of 4 cm3. Calculate the density of the unknown substance.
myrzilka [38]

Answer:

Density is 3.75g/cm3

Explanation:

Density = mass ÷ volume

= 15g ÷ 4cm3

= 3.75g/cm3

5 0
3 years ago
( TRUE false )
Alex73 [517]

Answer:

number 6 is wrong

the answer is pesticides

2.combines are used for harvesting or threshing.so number <em>2</em><em> </em><em>is</em><em> </em><em>w</em><em>rong</em>

at least you tried

Explanation:

there is no such thing as <em>weedicides</em>

8 0
3 years ago
Read 2 more answers
Which would most likely have a direct effect on using wave power to generate electricity?
Nadya [2.5K]

Answer: I would either say wind or sunlight

Explanation:

I don’t think it would be clouds or rain

Hope that helps

4 0
2 years ago
Read 2 more answers
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