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3 years ago

What are the top three osha cited ladder violations

Physics

1 answer:

bonufazy [111]3 years ago

6 0

Answer:

Explanation:

1. FALL PROTECTION-GENERAL REQUIREMENTS (29 CFR 1926.501) 6,010 VIOLATIONS

2. HAZARD COMMUNICATION (29 CFR 1910.1200). 3,671

3. SCAFFOLDING (29 CFR 1926.451). 2,813

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A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magne

Licemer1 [7]

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

<h3>Current in the wire</h3>

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

<h3>Magnetic field at the center of the loop</h3>

The magnetic field at the center of the circular loop is calculated as follows;

$B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T$

Learn more about magnetic field here: brainly.com/question/7802337

3 0

2 years ago

The orbitals can be found by counting down the _____.

KengaRu [80]

I think it's B for electrons

8 0

4 years ago

An astronaut is using a drill to fix the gyroscopes on the Hubble telescope. Suddenly she loses her footing and floats away from

Naddik [55]

The direction the telescope may be heading ummm honestly I don’t know the answer to that

8 0

3 years ago

A carpenter builds an exterior house wall with a layer of wood 3.0 cm thick on the outside and a layer of Styrofoam insulation 2

Leno4ka [110]

Answer:

A. T=15.54 °C

B. Q/A= 0.119 W/m2

Explanation:

To solve this problem we need to use the Fourier's law for thermal conduction:

$Q= kA\frac{dT}{dx}$

Here, the rate of flow per square meter must be the same through the complete wall. Therefore, we can use it to find the temperature at the plane where the wood meets the Styrofoam as follows:

$\frac{Q}{A} =\frac{T_1-T_0}{d_w}k_w=\frac{T_2-T_1}{d_s}k_s\\T_1(\frac{k_w}{d_w}+\frac{k_s}{d_s})=T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}\\T_1=\frac{T_2\frac{k_s}{d_s}+T_0\frac{k_w}{d_w}}{\frac{k_w}{d_w}+\frac{k_s}{d_s}}\\T_1= 15.54 \°C$

Then, to find the rate of heat flow per square meter, we have:

$\frac{Q}{A}=\frac{T_1-T_0}{d_w}k_w=0.119 \frac{W}{m^2}\\\frac{Q}{A}=\frac{T_2-T_1}{d_s}k_s= 0.119 \frac{W}{m^2}$

$T_0: Temperature \ in \ the \ house\\T_1: Temperature \ at \ the \ plane \ between \ wood \ and \ styrofoam\\T_2: Temperature \ outside\\k_w: k \ for \ wood\\d_w: wood \ thickness\\k_s: k \ for \ styrofoam\\d_s: styrofoam \ thickness$

7 0

3 years ago

A train is approaching you at very high speed as you stand next to the tracks. Just as an observer on the train passes you, you

VashaNatasha [74]

Answer:

a) Your player

b) Observer's player

c) Each measures their own first

Explanation:

Because given problem is having relative velocity to each other. The person sitting on the train is moving with a very high speed relative to the person standing next to the track.

In this case, the clock situated in the train will be running slow with respect to the stationary frame of reference

8 0

3 years ago