Answer:
the tension produce by the bird in the wire is 610.3 N.
Explanation:
given information:
mass of the bird, m = 1 kg
distance of two telephone pole, L = 50 m
wire sag, y = 0.2
the tension of the wire can be calculate by the following equation
tan θ = y/(L/2)
= 0.2/(50/2)
= 0.2/25
thus
θ = arc tan (0.2/25)
= 0.46°
according to Newton's first law
ΣF = 0, vertical direction
T sin θ + T sin θ - mg = 0
2 T sin θ = m g
T = mg/2 sinθ
= 1 x 9.8/(2 sin 0.46)
= 610.3 N
Spring tides occur twice each lunar month all year long (they don't depend on any particular season. When there is a new or full moon the average tidal ranges are larger.
M = 1250 kg
V = 14.0 m/s
t = 7.25 s
F = ?
Impulse equation
F . t = m . V
:. F = mv/t
F = (1250 kg x 14.0 m/s) / 7.25s
F = 2414 N
Answer:
The speed of washer will be 32.144 m/s
Explanation:
Given that
time t= 3.28 s
Acceleration due to gravity
Here acceleration is constant so we cam apply the motion equation
we know that
v= u + at
At initial condition u =0 m/s
v= u + at
v= 0 + 9.8 x 3.28
v= 32.144 m/s
So the speed of washer will be 32.144 m/s
