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krok68 [10]
3 years ago
9

7. A 3.0 kg object travels vertically at a constant

Physics
1 answer:
vladimir2022 [97]3 years ago
7 0

Answer:

220.7

Explanation:

distance traveled is 1.5*5=7.5m

PE gain is MGH=3*9.81*7.5=220.7

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The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. what is the a
bulgar [2K]

The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

To know more about the "general equation of SHM", refer to the link below:

brainly.com/question/14869852?referrer=searchResults

#SPJ4

6 0
2 years ago
_____ electrons are the most important electrons to an atom .
nalin [4]

Answer:

stable is the answer

Explanation:

stable electrons

8 0
3 years ago
Which one is the full moon?​
Svetlanka [38]

Answer:

The one to the left

Explanation:

6 0
3 years ago
The power in our homes and buildings cycles at a frequency of 60Hz. If someone accidentally dropped a power line into a holding
sp2606 [1]

Answer:

The answer is "Rigor mortis".

Explanation:

When the very large volume will be that the progress of its postponed by calcium and magnesium. The causes brain intensification of a liver due to the change throughout the myofibrils within a week of dying of its organism. When anyone accidentally spilled a power cable into a rank for toads, one's tissue will be disrupted instantly by stringent deaths.

8 0
3 years ago
Two soccer players start from rest, 36 m apart. They run directly toward each other, both players accelerating. The first player
Cerrena [4.2K]
A) Both players are moving by uniformly accelerated motion, and we can write the position at time t of each of the two players as follows:
x_1(t)= \frac{1}{2}a_1 t^2
x_2(t)=d- \frac{1}{2}a_2 t^2
where
a_1 = 0.58 m/s^2 is the acceleration of the first player
a_2=0.42 m/s^2 is the acceleration of the second player
d=36 m is the initial distance between the two players
and where I put a negative sign in front of the acceleration of the second player, since he's moving in the opposite direction of the first player.

The time t at which the two players collide is the time t at which x_1 = x_2, therefore:
\frac{1}{2}a_1 t^2 = d- \frac{1}{2}a_2 t^2
from whic we find
t= \sqrt{ \frac{2d}{a_1+a_2} }= \sqrt{ \frac{2 \cdot 36 m}{0.58 m/s^2+0.42 m/s^2} }=8.5 s

b) We can use the equation of x_1(t) to find how far the first player run in t=8.5 s:
x_1(t)= \frac{1}{2}a_1 t^2= \frac{1}{2}(0.58 m/s^2)(8.5 s)^2=21.0 m
8 0
3 years ago
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