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krok68 [10]
2 years ago
9

7. A 3.0 kg object travels vertically at a constant

Physics
1 answer:
vladimir2022 [97]2 years ago
7 0

Answer:

220.7

Explanation:

distance traveled is 1.5*5=7.5m

PE gain is MGH=3*9.81*7.5=220.7

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zmey [24]

Answer:

F =1490.9 N

Explanation:

given,

work done = 82 J

compression length = 0.220 m

for parallel combination

k_{eq}= k_1+k_2

         = 2 k

work done

w = \dfrac{1}{2}k_{eq}x^2

k_{eq} = \dfrac{2W}{x^2}

k_{eq} = \dfrac{2\times 82}{0.22^2}

k_{eq} =3388.43 N/m

force =

F = kx

F = 3388.43 ×0.22

F =745.45 N

the additional work done

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maximum force

F = k × 2x

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