Complete question:
A hydraulic jack is used to lift a car by applying a force of 120N at the pump piston, if the area of the ram and pump piston are 100cm squared and 1m squared respectively. What is the weight of the car?
Answer:
the weight of the car is 1.2 N
Explanation:
Given;
applied force, F₁ = 120 N
area of the effort (pump), A₁ = 1 m²
area of the load (ram), A₂ = 100 cm² = 1 x 10⁻² m²
let the weight of the car = F₂
The applied pressure is constant and the following equations can be used to calculate the weight of the car.
Therefore, the weight of the car is 1.2 N
Therefore, it is safe to say that as the mass of an object<span> increases so does </span>its <span>inertia. ... Mass and </span>velocity<span> are both directly proportional to the </span>momentum<span>. </span>If<span> you increase either mass or </span>velocity<span>, the </span>momentum<span> of the </span>object<span> increases proportionally. </span>If<span> you </span>double<span> the mass or </span>velocity<span> you </span>double<span> the </span>momentum<span>.</span>
Well, first of all, you really shouldn't use ' W ' for the unit when you
talk about resistors.
You may have seen the resistors written as 6ω, 12ω, and 2ω in your
book or on the homework sheet. But that little symbol ' ω ' is not a ' w '.
It's the small Greek letter 'omega'. The CAPITAL omega is ' Ω '. It's used
to label resistors because it's short for "ohms". So the resistors in this
problem have resistances of 6Ω, 12Ω, and 2Ω, and we have to do some
manipulating of the individual resistors to find out what resistance the
battery actually sees.
The parallel combination of the first two resistors looks like a single
resistor, whose value is
1 / (1/6 + 1/12)
= 1 / (2/12 + 1/12)
= 1 / (3/12)
= 12/3 = 4Ω .
Now, that parallel combination is connected in series with 2Ω .
All three resistors together look like a single resistor of
4Ω + 2Ω = 6Ω .
So the battery thinks there's a single resistor connected to it,
with 6Ω of resistance. The current out of the battery is
I = V / R = (24v) / (6Ω) = 4 Amperes.
That 4 Amperes of current will split between the parallel resistors,
but it will ALL flow through the series 2Ω resistor because there's
no other path through that part of the circuit.
So the current through the 2Ω resistor is 4 Amperes. (B).
Note:
The POWER dissipated by the 2Ω resistor is
P = I² R = (4A)² · (2Ω) = 32 watts .
This is a fair amount of heat, so you'll need to provide some way
to remove the heat from the resistor, otherwise it'll burn or crack.
<em></em>Your answer is :<em>
A.
</em>
Groundwater.<em>
</em>
The missing part of the incomplete question is given below:
Which important step of scientific design is Shameka conducting?
repetition
replication
verification of results
using controlled variables
Answer:
Verification of results
Explanation:
The way toward gathering five examples of water from various sources is conveyed to confirm the outcome. By gathering water from five distinct areas of a similar source the analyst can genuinely find out the nature of the water in her region of remain.
On the off chance that after examples are tried it is found the water isn't sound, the outcomes would be acknowledged as it has been appropriately checked and a proper move would be made.
Thus, the correct answer is - verification of results