Answer:
Speed will be equal to 1.40 m/sec
Explanation:
Mass of the rubber ball m = 5.24 kg = 0.00524 kg
Spring is compressed by 5.01 cm
So x = 5.01 cm = 0.0501 m
Spring constant k = 8.08 N/m
Frictional force f = 0.031 N
Distance moved by ball d = 15.8 cm = 0.158 m
Energy gained by spring
Energy lost due to friction
So remained energy to move the ball = 0.0101 - 0.0048 = 0.0052 J
This energy will be kinetic energy
v = 1.40 m/sec
Answer:
l= 4 mi : width of the park
w= 1 mi : length of the park
Explanation:
Formula to find the area of the rectangle:
A= w*l Formula(1)
Where,
A is the area of the rectangle in mi²
w is the width of the rectangle in mi
l is the width of the rectangle in mi
Known data
A = 4 mi²
l = (w+3)mi Equation (1)
Problem development
We replace the data in the formula (1)
A= w*l
4 = w* (w+3)
4= w²+3w
w²+3w-4= 0
We factor the equation:
We look for two numbers whose sum is 3 and whose multiplication is -4
(w-1)(w+4) = 0 Equation (2)
The values of w for which the equation (2) is zero are:
w = 1 and w = -4
We take the positive value w = 1 because w is a dimension and cannot be negative.
w = 1 mi :width of the park
We replace w = 1 mi in the equation (1) to calculate the length of the park:
l= (w+3) mi
l= ( 1+3) mi
l= 4 mi
Present. NOT SURE IF THIS IS EVEN RIGHT!! I JUST GUESSED AND THOUGHT
Answer:
The strength of the electric field is 2.258 x 10⁸ N/C
Explanation:
Potential energy = -p*ECosθ
where;
d is the dipole moment
E is the electric field
θ is the angle of inclination
→When the water molecules is perpendicular to the field, θ =90° and potential energy = p*ECosθ = d*ECos0 = 0
Total potential energy = 0 + 1.40×10⁻²¹J, since it is 1.40×10⁻²¹J more
→When the water molecules is aligned to the field, θ =0°
potential energy = -p*ECosθ
dipole moment, p = 6.2×10⁻³⁰Cm
= -(6.2×10⁻³⁰)*(E) Cos0
0 + 1.40×10⁻²¹ J = -(6.2×10⁻³⁰)*(E),
E = (1.40×10⁻²¹ J)/(6.2×10⁻³⁰)
E = 2.258 x 10⁸ N/C
Therefore, the strength of the electric field is 2.258 x 10⁸ N/C
