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Lina20 [59]
3 years ago
9

What is your ideal high school experience?

Physics
2 answers:
Tomtit [17]3 years ago
4 0

Answer:

ever watched the movie mean girls.......... i wish it was like that lol

kupik [55]3 years ago
3 0

Answer:

High school sucks lol

Explanation:

You might be interested in
Heat would best be transferred by conduction between A) a candle and the air. B) an oven and a glass dish. C) a stove and a copp
postnew [5]

Answer: Option (C) is the correct answer.

Explanation:

Conduction is a process where transfer of heat occurs when two objects of different temperature are held next to each other. Heat gets transferred from hot substance to cool substance.

For example, when a copper pot is placed over a stove then heat transfers from stove to the copper pot.

Thus, we can conclude that heat would best be transferred by conduction between a stove and a copper pot.

6 0
2 years ago
A 5.0-kg object is pulled along a horizontal surface at a constant speed by a 15-n force acting 20° above the horizontal. How mu
puteri [66]

Answer:

84.6 J

Explanation:

The work done by the force is given by

W=Fd cos \theta

where

W is the work done

F = 15 N is the force applied

d = 6.0 m is the displacement

\theta=20^{\circ} is the angle between the force's direction and the displacement

Substituting the numbers into the equation, we find

W=(15 N)(6.0 m)cos 20^{\circ} =84.6 J

3 0
3 years ago
What was the average speed in km/h of a car that travels 400.0 km in 4.5 h?
Yanka [14]
V= s/t = 400/4.5=800/9 (km/h)
6 0
3 years ago
During a testing process, a worker in a factory mounts a bicycle wheel on a stationary stand and applies a tangential resistive
Katyanochek1 [597]

Answer:

The force is F = 1041.7N

Explanation:

The moment of Inertia I is mathematically evaluated as

               I = MR_A^2

Substituting  1.9kg for M(Mass of the wheel) and \frac{66cm}{2} * \frac{1m}{100cm} = 0.33m for R_A(Radius of wheel)

              I = 1.9 * 0.33^2

                = 0.207kgm^2

The torque on the wheel due to net force is mathematically represented as

                      \tau = FR_B  - F_rR_A

Substituting  135 N for F_r (Force acting on sprocket),\frac{8.7cm}{2} * \frac{1m}{100cm} = 0.0435m for R_B (radius of the chain) and F is the force acting on the sprocket due to the chain which is unknown for now

                     \tau = F (0.0435) - 135 (0.33)

This same torque due to the net force is the also the torque that is required to rotate the wheel to have an angular acceleration of \alpha  = 3.70 rad/s^2 and this torque can also be represented mathematically as

                   \tau = \alpha I

Now equating the two equation for torque

                                F (0.0435) - 135 (0.33) = \alpha I    

Making F the subject

                     F = \frac{\alpha I + (135*0.33) }{0.0435}

Substituting values

                  F = \frac{(3.70 * 0.207)  + (135*0.33)}{0.0435}

                       = 1041.7N

4 0
3 years ago
FCFrdfAQefgEwdfgedfsaewfdedasfewreagargferdfares
Ivan

Answer: AAAAAAAAGGGGGHHHHJJJGSSSUUUUUUUUYCCFVGBHNJM

Explanation: YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET YEET

6 0
3 years ago
Read 2 more answers
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