Answer:
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
2 moles of H₂O are on the reactant side.
Explanation:
Let´s consider the following half-reaction.
MnO₄⁻ ⇒ MnO₂
This reduction of permanganate to manganese dioxide happens in a neutral medium. The oxidation number of Mn changes from +7 to +4. When we are in a neutral medium, we can balance the reaction using the ion-electron method either as we were in acid or in basic medium. In this case, to satisfy the condition is the task (<em>water on the reactant side</em>) we will balance this half-reaction as if it were in basic media. Since Mn is already balanced, we have to balance O. We will add as many moles of water as excess of oxygen there is on 1 side, and the double of OH⁻ on the other side. Finally, we add as many electrons as we need to balance it electrically.
MnO₄⁻ + 2 H₂O + 3 e⁻ ⇒ MnO₂ + 4 OH⁻
<h3>Option c Deforestation.</h3>
<h2>I hope it will help you. </h2>
572.25 cm3 unless you're rounding to significant figures than it would be 572 cm3
Answer:
a solution of acetic acid and sodium acetate
Explanation:
A buffer solution is defined as a solution which resist a change in pH when small quantity of a strong acid or a strong base are added. A buffer solution is made up of mixture of a weak acid and its conjugate base or a mixture of a weak base and its conjugate acid.
Acetic acid is the only option because it is a weak acid with a corresponding conjugate base, acetate. Unlike a solution of sulfuric acid and sodium sulfate in which the sulfuric acid is a strong acid which doesn’t qualify it to be a buffer solution. The remaining options have different acid compounds paired together which makes them invalid too.
