Answer:
As light travels in a straight line at a constant speed, it's acceleration is <u>0 m/s²</u>.
There is no rate of change of speed, so there is no acceleration.
- <u>0 m/s²</u> is the right answer.
Answer:
m=417.24 kg
Explanation:
Given Data
Initial mass of rocket M = 3600 Kg
Initial velocity of rocket vi = 2900 m/s
velocity of gas vg = 4300 m/s
Θ = 11° angle in degrees
To find
m = mass of gas
Solution
Let m = mass of gas
first to find Initial speed with angle given
So
Vi=vi×tanΘ...............tan angle
Vi= 2900m/s × tan (11°)
Vi=563.7 m/s
Now to find mass
m = (M ×vi ×tanΘ)/( vg + vi tanΘ)
put the values as we have already solve vi ×tanΘ
m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)
m=417.24 kg
When blue litmus paper is dipped in acid the paper turns red.
hope this helps :)
Answer:
25.6 m/s
Explanation:
Draw a free body diagram of the sled. There are two forces acting on the sled:
Normal force pushing perpendicular to the hill
Weight force pulling straight down
Take sum of the forces parallel to the hill:
∑F = ma
mg sin θ = ma
a = g sin θ
a = (9.8 m/s²) (sin 38.0°)
a = 6.03 m/s²
Given:
v₀ = 0 m/s
a = 6.03 m/s²
t = 4.24 s
Find: v
v = at + v₀
v = (6.03 m/s²) (4.24 s) + (0 m/s)
v = 25.6 m/s
Answer:
Gravitational force mg' =(49)mg=49×63=28N.
Explanation:
What is the gravitational force on it due to the Earth , at a height equal to half the radius of the Earth ? (Given that the radius of Earth = 6400 km). Gravitational force mg ( This is not the real explanation)
