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horsena [70]
2 years ago
11

In which scenario will the two objects have the least gravitational force between them?​

Physics
2 answers:
yawa3891 [41]2 years ago
7 0

Answer:

A

Explanation:

Karo-lina-s [1.5K]2 years ago
6 0

Answer:b

Explanation:

Apx

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An astronaut landed on a far away planet that has a sea of water. To determine the gravitational acceleration on the planet's su
TiliK225 [7]

The concept required to solve this problem is hydrostatic pressure. From the theory and assuming that the density of water on that planet is equal to that of the earth (1000kg / m ^ 3)we can mathematically define the pressure as

P = \rho g h

Where,

\rho = Density

h = Height

g = Gravitational acceleration

Rearranging the equation based on gravity

g = \frac{P_h}{\rho h}

The mathematical problem gives us values such as:

P = 2.4 atm (\frac{101325Pa}{1atm}) = 243180Pa

\rho = 1000kg/m^3

h = 28.6m

Replacing we have,

g = \frac{243180}{(1000)(28.6)}

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3 0
2 years ago
Space pilot Mavis zips past Stanley at a constant speed relative to him of 0.800c. Mavis and Stanley start timers at zero when t
yawa3891 [41]

Answer:

a) x=2*10^{9} m and t=8.35 s

b) t = γt', so it is 8.35 s.

Explanation:

a) The equation of Lorentz transformations is given by:

x=\gamma(x'+ut')  

x' and t' are the position and time in the moving system of reference, and u is the speed of the space ship. x is related to the observer reference.

  • x' = 0
  • t' = 5.00 s
  • u =0.800 c, c is the speed of light 3*10⁸ m/s

\gamma=\frac{1}{\sqrt{1-(u/c)^{2}}}

\gamma=\frac{1}{\sqrt{1-(0.800c/c)^{2}}}

\gamma=\frac{1}{\sqrt{1-(0.800)^{2}}}

\gamma=1.67

x=1.67(0+0.800c*5.00)

x=2*10^{9} m

Now, to find t we apply the same analysis:

t=\gamma(t'+\frac{ux'}{c^{2}})                        

but as x'=0 we just have:

t=\gamma(t')

t=1.67*5.00=8.35 s

b) Here, Mavis reads 5 s on her watch and Stanley measured the events at a time affected by the Lorentz factor, in other words t = γt', if we see it is the same a) part. So the time interval will be equal to 8.35 s.

I hope it helps you!

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3 years ago
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(Look at the minerals in the linked picture)
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