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tatuchka [14]
3 years ago
13

Light travels in a straight line at a constant speed of 300000 m/s. What is the acceleration of light?

Physics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

As light travels in a straight line at a constant speed, it's acceleration is <u>0 m/s²</u>.

There is no rate of change of speed, so there is no acceleration.

  • <u>0 m/s²</u> is the right answer.
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A 3.5 kW drill transfers 5 000 kJ of kinetic energy during 15 seconds of use. What is the percentage efficiency of the drill?
Marizza181 [45]

Answer:

1.04%

Explanation:

Given that,

The power of drill = 3.5 kW = 3500 W

Transferred kinetic energy = 5000 kJ during 15 seconds of use.

We need to find the percentage efficiency of the drill. It can be given by :

\eta=\dfrac{P_o}{P_i}\times 100

Where

Po and Pi are output and input powers.

P_o=\dfrac{5000\times 10^3}{15}\\\\=3.34\times 10^5\ W

So,

\eta=\dfrac{3500}{3.34\times10^{5}}\times100\\\\=1.04\%

So, the percentage efficiency of the drill is 1.04%.

4 0
3 years ago
Which of the following is a correct step in the process of adding 8.0 x 10^ -2 and 6.0 x 10^ -3
dybincka [34]

Explanation:

In order to compute correctly the sum of the two terms, we have to rewrite one of them such that they have the same exponent.

The two terms are:

8.0 \cdot 10^{-2}

6.0 \cdot 10^{-3}

For instance, we can re-write the second term such as it also has a power 10^{-2}. In order to do that, we have to move the decimal point one place to the left, therefore:

6.0 \cdot 10^{-3} = 0.6\cdot 10^{-2}

At this point, the two numbers have the same exponent, so we can just add them together by adding the bases and keeping the same exponent, -2:

8.0\cdot 10^{-2} + 0.6 \cdot 10^{-2} = (8.0 + 0.6) \cdot 10^{-2} = 8.6\cdot 10^{-2}

8 0
4 years ago
The table shows the potential energy and kinetic energy of a skier at two different positions on a hill.
Serggg [28]

Answer:

30,000 units, because total energy remains unchanged

6 0
3 years ago
Read 2 more answers
PE:
ella [17]

Answer:

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

7 0
3 years ago
A 120 V potential difference is applied to a space heater that dissipates 674 W during operation. (a) What is its resistance dur
Annette [7]

Answer:

(a) 21.36 ohms

(b) 5.62 A

Explanation:

Parameters given:

Potential difference, V = 120 V

Power, P = 674 W

(a) Power is given as:

P = V²/R

Where R is resistance

=> R = V²/P

R = 120²/674

R = 14400/674

R = 21.36 ohms

(b) Power is also given as:

P = I*V

Where I = Current (time rate of flow of Electric charge)

=> I = P/V

I = 674/120

I = 5.62 A

6 0
3 years ago
Read 2 more answers
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