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gizmo_the_mogwai [7]
3 years ago
6

I would likefor someone to help me indetify What is matter ?

Chemistry
2 answers:
Marysya12 [62]3 years ago
6 0
Anything that has mass and takes up space
OverLord2011 [107]3 years ago
3 0
Matter is anything that has mass and takes up space. Ex: You're pencil you write with. The food you eat. The floors you walk on. 
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An experiment requires 0.52 M NH3(aq). The stockroom manager estimates that 15 L of the base is needed. What volume of 15 M NH3(
Bingel [31]

Answer: 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base.

Explanation:

But on diluting the number of moles remain same and thus we can use molarity equation.

C_1V_1(stock)=C_2V_2 (to be prepared)

where,

C_1 =concentration of stock solution = 15 M

V_1 = volume of stock solution = ?

C_2 = concentration of solution to be prepared = 0.52 M

V_2 = volume of solution to be prepared = 15 L

15\times V_1=0.52\times 15

V_1=0.52L

Thus 0.52 L of 15 M NH_3(aq) will be used to prepare this amount of 0.52 M base

8 0
3 years ago
Which two temperatures are equivalent?
S_A_V [24]

Answer:

273 °K annd 0°C are equivalent

3 0
3 years ago
The number of mgs of Cl- in a 750 mL bottle of mineral water is 21
love history [14]

Answer:

For instance, one liter of Mendocino mineral water contains more than 30% of the Ca2+ and Mg2+ DRIs in adult women, and 1 liter of Vichy .

Explanation:

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3 0
3 years ago
Given the following balanced chemical reaction:
Gnom [1K]

Answer:

Explanation:

according to balance chemical equation

  3 A2 moles produced 2 moles of A3B

so 12 moles A2 will produced moles of A3B= 12*2/3=24/3= 8

therefore 12 moles of A2 produced 8 moles of A3B

6 0
4 years ago
In the determination of the specific heat of a metal, why is it desirable to use the minimum volume of water that will allow imm
Softa [21]

Answer:

Because it will allow a bigger temperature change.

Explanation:

The specific heat of the metal can be calculated by the heat change between it and the water. The total amount of heat must be 0, thus, the heat of the metal (Qm) plus the heat of water (Qw):

Qm + Qw = 0

The heat is the mass multiplied by the specific heat (c) and by the temperature change:

mm*cm*ΔTm + mw*cw*ΔTw = 0

mm*cm*ΔTm = - mw*cw*ΔTw

So, as higher is the value of mw, as low is the value of ΔTw, and if ΔTw is very low, and so the calculations may not be precise.

7 0
3 years ago
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