Since BC is the hypotenuse...
α = 12
c = 13
Hence..
13² = 12² + ß²
ß = √(13² - 12²)
= √(169 - 144)
= √25
= 5
Hence, AB = 5
I hope this helps!
X = 32.5 I believe..........
It's almost solved. Just move the -2 to the other side.
n^2-10n+22=-2
n^2-10n+24 done!
No; a range value has two domain values.
