Question

What is the molar concentration of 250. mL of aqueous solution containing 48.8 g of glucose, C6H12O6?

Answer 1

Answer:

1.08 mol/L

Explanation:

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

$M=\frac{n}{V}$

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),  

n = moles of solute ( unit = mol ),  

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,

$n=\frac{w}{m}$

n = moles ,

w = given mass ,

m = molecular mass .

From the information of the question ,

V = 250 mL

Since ,

1 mL = 1/1000L

V = 0.250 L

w = 48.8 g

As we known , the mass of glucose ,

m = 180g/mol ,

From the above formula , moles is given as ,

$n=\frac{w}{m}$

substituting the corresponding values ,  

n = 48.8g / 180g/mol

n = 0.27 mol

Now , the molarity can be calculated by using the above equation ,

M = n / V

substituting the corresponding values ,  

M = 0.27 mol /  0.250 L

M = 1.08 mol/L