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3 years ago

Electroysis is used for

Chemistry

1 answer:

Alina [70]3 years ago

4 0

Answer:

Electrolysis is used extensively in metallurgical processes, such as in extraction (electrowinning) or purification (electrorefining) of metals from ores or compounds and in deposition of metals from solution (electroplating).

Explanation:

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What is the electrical charge of an atom that has gained an electron

BARSIC [14]

An electron has a ( - ) charge and so if an atom gains one electron it gains a - charge

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4 years ago

If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em

erica [24]

Answer: Wavelength associated with the fifth line is 397 nm

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $10973731.6m^{-1}$

$n_f$ = Higher energy level = 7

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

$\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2$

$\frac{1}{\lambda}=2.52\times 10^{6}m$

$\lambda}=3.97\times 10^{-7}m=397 nm$ $1nm=10^{-9}m$

Thus wavelength λ associated with the fifth line is 397 nm

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4 years ago

Elements are arranged in the periodic table based on various patterns. For example, elements found in the rows near the top

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The rows are called periods

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3 years ago

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State relationship between the level of dissolved oxygen and water temperature

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More dissolved oxygen is present in water with a lower temperature compared to water with a higher temperature. The reason for this inverse relationship between dissolved oxygen and temperature is that the solubility of a gas in a liquid is an equilibrium phenomenon.

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4 years ago

Jamal was riding his bike home at a speed of 12 mph. On his trip out, he had traveled 8 miles away from his house. He has been t

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Jamal is 2 miles away from his home.

Option B.

<h3><u>Explanation:</u></h3>

The initial distance of Jamal from his home is 8 miles. He needs to return home from his trip.

The speed that Jamal kept was constant for 30minutes and he drove at a speed for 12 miles per hour.

Speed of Jamal = 12 mph.

Time of travel = 30minutes =0.5 hours.

So distance traveled by Jamal = $12 \times0.5$ miles. = 6miles.

Initial distance of Jamal = 8 miles.

So final distance = $8-6$ miles = 2miles.

So Jamal is 2 miles away from his home.

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3 years ago

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Electroysis is used for ​

Electroysis is used for