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2 years ago

PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS!

Mathematics

2 answers:

Nataly_w [17]2 years ago

8 0

Answer:

see attached diagram

Step-by-step explanation:

Angle Bisector

The angle bisector bisects the angle into two equal angles.

Measure the angle EDF (I've measured this as 115°)

Divide this by 2: 115 ÷ 2 = 57.5°

Measure an angle of 57.5° from point D on the line DF and draw a line.

Parallel lines

Measure two lines of equal length from points X and Y at an angle of 90° to the line XY. Join the points for the parallel line.

The angle bisector and parallel line are shown in red on the attached diagram.

ohaa [14]2 years ago

6 0

Answer:

1)An angle bisector is basically the division of an angle into two equal parts, so you should just draw a line in the middle after you found the angles using the compass

2) parallel lines is a pair of lines that never intersect, and are always the same distance apart. you should use the compass to draw a 90-degree angle at the end of the line XY, and use the straightedge to draw a line that is parallel to the line XY.

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(2x-2) (x+5) what does x =

Lynna [10]

Answer:

the two roots of the equation take the form

−

√

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√

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(

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You can simplify this if you want to get

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4 0

2 years ago

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I need some help graphing this

Romashka [77]

Answer:

1.512445e+216

Step-by-step explanation:

3 0

3 years ago

Find the area of rectangle with sides 2 5/6 and 4 4/7

g100num [7]

<h3>Given :</h3>

Length = $\sf2\dfrac{5}{6}$ cm.
Breadth = $\sf4\dfrac{4}{7}$ cm.

The area of rectangle.

<h3>Solution :</h3>

Area of rectangle = Length × Breadth

$\sf=2\dfrac{5}{6}\times4\dfrac{4}{7}$

$\sf=\dfrac{17}{6}\times\dfrac{25}{7}$

$\sf=\dfrac{17\times25}{6\times7}$

$\sf=\dfrac{425}{42}$

<h3>Area of rectangle is 425/42 cm².</h3>

4 0

3 years ago

Read 2 more answers

Use the diagram to determine which statement is true

hichkok12 [17]

A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.

5 0

3 years ago

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Given the function h(x) =1/3 |x-6| +4, evaluate the function when x = - 3, - 2, and 0

Masja [62]

|x| = x for x ≥ 0

examples:

|3| = 3; |0.56| = 0.56; |102| = 102

|x| = -x for x < 0

examples:

|-3| = -(-3) = 3; |-0.56| = -(-0.56) = 0.56; |-102| = 102

--------------------------------------------------------------------------------

Use PEMDAS:

P Parentheses first

E Exponents (ie Powers and Square Roots, etc.)

MD Multiplication and Division (left-to-right)

AS Addition and Subtraction (left-to-right)

--------------------------------------------------------------------------------

$h(x)=\dfrac{1}{3}|x-6|+4$

Put the values of x to the equation of the function h(x):

$x=-3\to h(-3)=\dfrac{1}{3}|-3-6|+4=\dfrac{1}{3}|-9|+4=\dfrac{1}{3}(9)+4=3+4=7\\\\x=-2\to h(-2)=\dfrac{1}{3}|-2-6|+4=\dfrac{1}{3}|-8|+4=\dfrac{1}{3}(8)+4=\dfrac{8}{3}+\dfrac{12}{3}=\dfrac{20}{3}\\\\x=0\to h(0)=\dfrac{1}{3}|0-6|+4=\dfrac{1}{3}|-6|+4=\dfrac{1}{3}(6)+4=2+4=6$

6 0

3 years ago