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gavmur [86]
3 years ago
11

Which is the other endpoint of a line segment with one endpoint at 1,3 and midpoint at 3,5

Mathematics
1 answer:
Nookie1986 [14]3 years ago
6 0
One endpoint at 1,3 and the midpoint at 3,5
Your answer would be to as two to each the x and y of the midpoint. so 5,7
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If f(x) = 2x2 - 5 and g(x) = x2 - 4x - 8, find (f - g)(x).
oksano4ka [1.4K]

Answer:

B. ) x² + 4x + 3

Step-by-step explanation:

(f-g)(x) = f(x) - g(x) =

(2x²-5) - (x²-4x-8) =

2x² - x² + 4x + 8 - 5 =

x² + 4x + 3

8 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
The diagram below shows several parking spots near the grocery store, formed with three parallel line segments and a transversal
Marina CMI [18]
Something I noticed about angle 4, is that it shares a straight line with angle 3. (above it is a straight line)

A straight line equals 180 degrees.

So, angle 4 + angle 3= 180 degrees.

Angle 3 is congruent to angle 7.

180-132= Angle 7

180-132= 48

48 degrees is your answer.

I hope this helps!
~kaikers

8 0
4 years ago
Read 2 more answers
How do you add vectors? Add the vector <3,4> to the vector that goes 7 units at an angle of 2π/3.
lawyer [7]

Answer:

The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

Step-by-step explanation:

The horizontal component (x) of a vector whose magnitude is b units and its direction is Ф° is b cos Ф

The vertical component (y) of a vector whose magnitude is b and its direction is Ф is b sin Ф

The vector is <b cos Ф , b sin Ф>

∵ The vector goes 7 units at an angle \frac{2\pi }{3}

- That means its magnitude is 7 and its direction is  \frac{2\pi }{3}

∴ x = 7 cos(  \frac{2\pi }{3} )

∴ y = 7 sin(  \frac{2\pi }{3} )

∵ cos(  \frac{2\pi }{3} ) =  -\frac{1}{2}

∵ sin(  \frac{2\pi }{3} ) =  \frac{\sqrt{3}}{2}

- Substitute them in x and y

∴ x = (7)( -\frac{1}{2} )

∴ x = -3.5

∴ y = (7)( \frac{\sqrt{3}}{2} )

∴ y = 3.5\sqrt{3}

∴ The vector is <-3.5 , 3.5\sqrt{3}>

Now lets add the vectors by adding xs and ys components

∵ <3 , 4> + <-3.5 , 3.5\sqrt{3} > = <3 + -3.5 , 4 + 3.5\sqrt{3} >

∴  <3 , 4> + <-3.5 , 3.5\sqrt{3}> = <-0.5 , 4+3.5\sqrt{3} >

∴ The sum of the two vectors is the vector <-0.5 , 4+3.5\sqrt{3} >

5 0
3 years ago
Fill in the blanks to show the steps in solving the inequality -2x + 12&lt;-4
professor190 [17]
-2x + 12 < - 4......subtract 12 from both sides
-2x + 12 - 12 < -4 - 12....simplify
-2x < -16...divide both sides by -2, changing the inequality sign
(-2/-2)x > -16/-2....simplify
x > 8
8 0
3 years ago
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